X+1+X+1+X+X=50
4x+2=50
4x=48
X=12
Width is 12
Length is 13
Using the binomial distribution, it is found that there is a 0.8295 = 82.95% probability that at least 5 received a busy signal.
<h3>What is the binomial distribution formula?</h3>
The formula is:


The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- 0.54% of the calls receive a busy signal, hence p = 0.0054.
- A sample of 1300 callers is taken, hence n = 1300.
The probability that at least 5 received a busy signal is given by:

In which:
P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4).
Then:






Then:
P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0009 + 0.0062 + 0.0218 + 0.0513 + 0.0903 = 0.1705.

0.8295 = 82.95% probability that at least 5 received a busy signal.
More can be learned about the binomial distribution at brainly.com/question/24863377
#SPJ1
Answer:
Alternative C is the correct answer
Step-by-step explanation:
The first step is to determine the composite function;
![f[g(x)]](https://tex.z-dn.net/?f=f%5Bg%28x%29%5D)
![f[g(x)]=cos[cot(x)]](https://tex.z-dn.net/?f=f%5Bg%28x%29%5D%3Dcos%5Bcot%28x%29%5D)
We then employ a graphing utility to determine the range and the domain of the new function.
The range is the set of y-values for which the function is defined. In this case it is;
![[-1,1]](https://tex.z-dn.net/?f=%5B-1%2C1%5D)
On the other hand, the domain refers to the set of the x-values for which the function is real and defined. In this case; it is the set of real numbers x except x does not equal npi for all integers n.
Just squish the two equations into one equation and idk im just typing this because i apparently need a twenty character long answer
Answer:
b.
Step-by-step explanation: