Answer:
A.
= Cube root of 4.
Step-by-step explanation:
We have been given an expression
. We are asked to find the equivalent expression for our given expression.
Using exponent property
, we will get,
![2^{\frac{2}{3}}=\sqrt[3]{2^2}](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B2%5E2%7D)
![2^{\frac{2}{3}}=\sqrt[3]{4}](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B4%7D)
Upon looking at our given choices, we can see that option A is the correct choice.
Two of them are 1/4 and 2/8! Hope this helps:)
Answer:
Step-by-step explanation
Hello!
Be X: SAT scores of students attending college.
The population mean is μ= 1150 and the standard deviation σ= 150
The teacher takes a sample of 25 students of his class, the resulting sample mean is 1200.
If the professor wants to test if the average SAT score is, as reported, 1150, the statistic hypotheses are:
H₀: μ = 1150
H₁: μ ≠ 1150
α: 0.05
![Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~~N(0;1)](https://tex.z-dn.net/?f=Z%3D%20%5Cfrac%7BX%5Bbar%5D-Mu%7D%7B%5Cfrac%7BSigma%7D%7B%5Csqrt%7Bn%7D%20%7D%20%7D%20~~N%280%3B1%29)

The p-value for this test is 0.0949
Since the p-value is greater than the level of significance, the decision is to reject the null hypothesis. Then using a significance level of 5%, there is enough evidence to reject the null hypothesis, then the average SAT score of the college students is not 1150.
I hope it helps!
Answer:
2.807
Step-by-step explanation:
In order to make comparisons between two numbers we use ratios.
Ratios can be written as fraction, with a colon or with the word to.
The ratio 52,853:18,827 or
52,853/18,827 = 2.807