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Nimfa-mama [501]
3 years ago
14

Last Wednesday, students could choose ham or turkey sandwiches for lunch. The cafeteria made 75 sandwiches in all, 51 of which w

ere turkey. What percentage of the sandwiches were turkey sandwiches?
Mathematics
1 answer:
exis [7]3 years ago
7 0

Answer:

0.68%

Step-by-step explanation:

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The quantity demanded x for a product is inversely proportional to the cube of the price p for
Harrizon [31]
X = k/p^3
125 = k/10^3 = k/1000
1000 x 125 = k
k = 125000

x = 125000/p^3

The profit is given by G = px - (125 + 2x) = p(125000/p^3) - 125 - 2(125000/p^3) = 125000/p^2 - 250000/p^3 - 125
For maximum profit:
dG/dp = 0
dG/dp = -250000/p^3 + 750000/p^4 = 0
750000 - 250000p = 0
p = 750000/250000 = 3

Therefore the price that will yeaild maximum profit is $3.
6 0
4 years ago
Use the drawing tool(s) to form the correct answer on the provided graph.
AlekseyPX

The solutions to the system of equations are (-2,-6) and (4,6)

<h3>How to determine the system of equations?</h3>

We have:

-2x + y = -2

y = -\frac12x^2 + 3x + 2

Next, we plot the graph of both functions.

From the attached graph, the equations intersect at (-2,-6) and (4,6)

Hence, the solutions to the system of equations are (-2,-6) and (4,6)

Read more about system of equations at:

brainly.com/question/21405634

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5 0
2 years ago
Given that a = -1, b=2 and c= -3 ,find the value of a(b2+c2)
KiRa [710]

Answer:

a(b^{2}+c^{2}) = = -13

Step-by-step explanation:

Given that a = -1, b=2 and c= -3

find the value of a(b^{2}+c^{2})

Just substitute the values given for each variable

a(b^{2}+c^{2}) = (-1)(2^{2}+(-3)^{2}) ; do the exponents first

a(b^{2}+c^{2}) = (-1)(4+9)=(-1)(13) ; now add inside the parenthesis;

a(b^{2}+c^{2}) = -13 ; and multiply by -1

7 0
3 years ago
Which diagram shows possible angle measures of a triangle?
alex41 [277]

Answer: 35 degrees, 35 degrees, and 120 degrees

Step-by-step explanation:

4 0
4 years ago
What is the next greatest number of tens 384
Umnica [9.8K]

Answer:

9

step by step explanation :

390

<em>Hope</em><em> this</em><em> helps</em><em> </em><em>:</em><em>)</em>

5 0
3 years ago
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