Answer:

Step-by-step explanation:
when adding logs, apply the log rule: 
∴ 
when subtracting logs, apply the log rule: 


For each boy, there are 5 girls
On Monday she made 50 throws.
On Tuesday she made 56 throws.
a) The increase is just how much more she made the next day.
56 - 50 = 6
She had an increase of 6 free throws.
b) To find the percent increase, all you do is divide the two numbers.
56/50 = 1.12
To change that into a percentage, either multiply it by 100 or move the decimal point two places to the right.
1.12 × 100 = 112
She had a 112% increase in her free throws.
The answer is:
D. 6; 112%
Answer:
0.16
Step-by-step explanation:
This question isn't phrased correctly, but I will assume it's asking about common denominators with fractions.
9/11 1/22
18/22 1/22
18 school days.