Answer:
y=-5x+19
Step-by-step explanation:
yeah -ya...... right?
Answer:
1)b=-4
2)k=4
3)can u explain what #3 and 4 say
4)?
5)0/ no solution
Step-by-step explanation:
Do both as equation it will make it easier for her
Selections 2, 3, 5, 6 are polynomials.
1 and 4 are not. The coefficients don't have to be integers, but the powers of the variables need to be positive integers. In 1, you have x^-1. in 4, you have x^(1/2).
<span>Here let the quadratic equation be ax^2 + bx + c
We know that a=5 from the question.
Since the roots are 6 and 2, the quadratic equation would take the form of a product like (a1x-b1)(a2x-b2).
However, let's assume that a2=1 and b2=6,
Since a=5, a1=5, then 5x-b1=5(x-2). Solving this shows that b1=10
So, the equation is (5x-10)(x-6)</span>
