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2 years ago

-1 - ( -2 ) = Can you help me with this question :)

Mathematics

2 answers:

attashe74 [19]2 years ago

7 0

Answer:1

Solution Steps

−1−(−2)

The opposite of −2 is 2.

−1+2

Add −1 and 2 to get 1.

wolverine [178]2 years ago

4 0

Answer:

-1 - ( -2 ) = 1

Step-by-step explanation:

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A set whose elements belong to a given set element 2 . a number that can be written as a ratio in fraction form irrational numbe

Gre4nikov [31]

A set whose elements belong to a given set : subset
a number that can be written as a ratio in faction form : rational number
a number in decimal form that does not terminate or repeat : irrational number
a number that can be written as an infinite decimal : real number
a collection or group of objects : set
a diagram that shows the relationship between sets : venn diagram
an object that belongs to the set : element

5 0

2 years ago

The perimeter of a rectangular field is 52 yards. The length is 4 more yards than the width. Find the length and width of the fi

hichkok12 [17]

:) Brainliest pls?

Answer:

Width = 11 yards

Length = 15 yards

Step-by-step explanation:

P = 2(l + w)

Consider the width to be x.

The length would then be x+4.

We know that P = 52 yd

52 = 2(x + x + 4)

52 = 2(2x + 4)

52 = 4x + 8 (Subtract 8 from both sides)

44 = 4x (Divide both sides by 4)

x = 11

The width is x, so the width is 11 yards.

The length is x+4, so the length is 15 yards.

8 0

3 years ago

Given the quadratic function f(x) = 4x^2 - 4x + 3, determine all possible solutions for f(x) = 0

solong [7]

Answer:

The solutions to the quadratic function are:

$x=i\sqrt{\frac{1}{2}}+\frac{1}{2},\:x=-i\sqrt{\frac{1}{2}}+\frac{1}{2}$

Step-by-step explanation:

Given the function

$f\left(x\right)\:=\:4x^2\:-\:4x\:+\:3$

Let us determine all possible solutions for f(x) = 0

$0=4x^2-4x+3$

switch both sides

$4x^2-4x+3=0$

subtract 3 from both sides

$4x^2-4x+3-3=0-3$

simplify

$4x^2-4x=-3$

Divide both sides by 4

$\frac{4x^2-4x}{4}=\frac{-3}{4}$

$x^2-x=-\frac{3}{4}$

Add (-1/2)² to both sides

$x^2-x+\left(-\frac{1}{2}\right)^2=-\frac{3}{4}+\left(-\frac{1}{2}\right)^2$

$x^2-x+\left(-\frac{1}{2}\right)^2=-\frac{1}{2}$

$\left(x-\frac{1}{2}\right)^2=-\frac{1}{2}$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solving

$x-\frac{1}{2}=\sqrt{-\frac{1}{2}}$

$x-\frac{1}{2}=\sqrt{-1}\sqrt{\frac{1}{2}}$ ∵ $\sqrt{-\frac{1}{2}}=\sqrt{-1}\sqrt{\frac{1}{2}}$

$\sqrt{-1}=i$

$x-\frac{1}{2}=i\sqrt{\frac{1}{2}}$

Add 1/2 to both sides

$x-\frac{1}{2}+\frac{1}{2}=i\sqrt{\frac{1}{2}}+\frac{1}{2}$

$x=i\sqrt{\frac{1}{2}}+\frac{1}{2}$

also solving

$x-\frac{1}{2}=-\sqrt{-\frac{1}{2}}$

$x-\frac{1}{2}=-i\sqrt{\frac{1}{2}}$

Add 1/2 to both sides

$x-\frac{1}{2}+\frac{1}{2}=-i\sqrt{\frac{1}{2}}+\frac{1}{2}$

$x=-i\sqrt{\frac{1}{2}}+\frac{1}{2}$

Therefore, the solutions to the quadratic function are:

$x=i\sqrt{\frac{1}{2}}+\frac{1}{2},\:x=-i\sqrt{\frac{1}{2}}+\frac{1}{2}$

4 0

2 years ago

The point A(-8, 6) is translated using T: (x,y) → (x + 5. y - 4). What is the distance from A to A'?

Vsevolod [243]

Translated means the points are moving across the plane without rotating or changing shape. In this case, the x-coordinate would be moving up 5 (x + 5) and the y-coordinate would be moving to the left 4 (y - 4).

A is (-8, 6). A' is the result of the translation from this point. The results of the solution above in A is the point (-3, 2) = A'.

Now you must find the distance between these two coordinates. To find the distance you must use the distance formula: √<span>(x2 - x1)^2 + (y2 - y1)^2. Since you now have two points, A and A', plug these into the distance formula.

</span>√(-3 - (-8))^2 + (2 - 6)^2
√5^2 + (-4)^2
√25 + 16
√41

The distance from A to A' is √41.

8 0

3 years ago

Read 2 more answers

What is the solution?

galina1969 [7]

Answer:

y=60 x=16

Step-by-step explanation:

the triangles are identical so 92+y=3y-28 so solve that for y:

-y +28

120=2y . /2 /2

60 = y so y=60

and 6x+2=3x+50 and solve that for x: which gets x = 16

Then are you supposed to plug it in to the numerical equvilant to the angles and sides becuase if so: B and E is 152, AC and DF are 98

Hope this helps and brainliest would be greatly appreciated! Thanks!

4 0

2 years ago