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1 year ago

-1 - ( -2 ) = Can you help me with this question :)

Mathematics

2 answers:

attashe74 [19]1 year ago

7 0

Answer:1

Solution Steps

−1−(−2)

The opposite of −2 is 2.

−1+2

Add −1 and 2 to get 1.

wolverine [178]1 year ago

4 0

Answer:

-1 - ( -2 ) = 1

Step-by-step explanation:

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Find the fifth term in a sequence: 15,20,25... A) 20 B) 45 C) 35 D) 40

guajiro [1.7K]

Answer:

C. 35

Step-by-step explanation:

Use the equation: y= 10+5x

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3 years ago

The population standard deviation for the temperature of beers found in Scooter's Tavern is 0.26 degrees. If we want to be 90% c

siniylev [52]

Answer:

19 beers must be sampled.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.9}{2} = 0.05$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.05 = 0.95$ , so Z = 1.645.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

The population standard deviation for the temperature of beers found in Scooter's Tavern is 0.26 degrees.

This means that $\sigma = 0.26$

If we want to be 90% confident that the sample mean beer temperature is within 0.1 degrees of the true mean temperature, how many beers must we sample?

This is n for which M = 0.1. So

$M = z\frac{\sigma}{\sqrt{n}}$

$0.1 = 1.645\frac{0.26}{\sqrt{n}}$

$0.1\sqrt{n} = 1.645*0.26$

$\sqrt{n} = \frac{1.645*0.26}{0.1}$

$(\sqrt{n})^2 = (\frac{1.645*0.26}{0.1})^2$

$n = 18.3$

Rounding up:

19 beers must be sampled.

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2 years ago

Jett has to sell carnival tickets worth at least $50. The price of a child ticket is $4, and the price of an adult ticket is $6.

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Answer: 4x + 6y >/ 50

Step-by-step explanation:

The answer is A. 4x + 6y is greater than or equal to 50

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2 years ago

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Answer:

B) 4

Step-by-step explanation:

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So, the angle of depression from the lighthouse to the boat is 4.

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Fittoniya [83]

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