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3 years ago

Combine the like terms to create an equivalent expression -3x-6+(-1)

Mathematics

1 answer:

Molodets [167]3 years ago

7 0

The answer on a app i have says it’s -3x - 7 so the person above me is right

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Can someone solve this?

insens350 [35]

Answer:

<h3> Jake is 13 years old</h3>

Step-by-step explanation:

D - age of Dani

J = D+2 - age of Jake

E = 2J = 2(D+2) = 2D+4 - age od Ethan

Z = 2E = 2(2D+4) = 4D+8 - age of Zoe

The sum of their ages is 102:

D + J + E + Z = 102

D + D+2 + 2D+4 + 4D+8 = 102

8D + 14 = 102

-14 -14

8D = 88

÷8 ÷8

D = 11

J = 11+2 = 13

7 0

3 years ago

2x-4=10 reverse order algebra

hjlf

Answer:

Step-by-step explanation:

2x-4=10

2x=10+4

2x=14

x=14/2

x=7

8 0

3 years ago

if about 32,834.5 kilobytes of memory is still available how many more pictures can they take if you have only taken 43 pictures

oksano4ka [1.4K]

That will depend, you have to ask yourself first how many kilobytes one picture is. Let's just say that the size of one picture is 100 kb (which is the average size of a picture) Then first you multiply 100 kb with the number of pictures which is 43. Now you have a total used up memory of 4300 kb. After that, you minus the used up memory which is 4300 kb, to the total available space which is 32,834.5 and you will get an available space of 28534.5 kb. After that, you divide the remaining available space with the size of each picture. So this will be 28534.5 divided by 100. You will get 285. You can still take 285 pictures.

5 0

3 years ago

Solve the quadratic equation.<br>m^2/15 -3 = 2

Radda [10]

The answer is $5 \sqrt{3}$

<h3>Explanation :</h3>

$\frac{ {m}^{2} }{15} - 3 = 2$

$\frac{ {m}^{2} }{15} = 2 + 3$

$\frac{ {m}^{2} }{15} = 5$

${m}^{2} = 5 \times 15$

${m}^{2} = 75$

$m = \sqrt{75}$

$m = \sqrt{25 \times 3}$

$m = \sqrt{25} \times \sqrt{3}$

$m = 5 \sqrt{3}$

CMIIW

7 0

3 years ago

A business executive bought 40 stamps for

alekssr [168]

Answer:

32 33-cent stamps, 8 23-cent stamps

Step-by-step explanation:

In order to solve this question, we need to set up a system of equations. Also known as solving for two variables (the number of each stamp).

Let's set x to be the number of 33-cent stamps. Similarly, let's set y to be the number of 23-cent stamps.

To make our first equation, let's think about the number of stamps total we have. We can say:

$x + y =40$

<em>(AKA - The number of 33-cent stamps, plus the number of 23-cent stamps, equals 40 stamps.)</em>

Now, let's make an equation for the cost of these stamps.

$0.33x + 0.23y = 12.40$

<em>(AKA - The cost of the stamps in total, should equal $12.40).</em>

So now, we have our two equations:

$x + y =40\\0.33x+0.23y=12.40$

If you have a TI-84 graphing calculator, you can go to apps -> polysmlt2 -> simultaneous eqn solver, and then input these equations into the menu. This will solve the problem for you.

If you need to do this manually, let's use substitution. Condense our first equation to make it more substitutable.

$x+y=40\\x=40-y$