Answer:
Total interest =$1296
Step-by-step explanation:
Kevin invested $8,000 for one year at a simple annual interest rate of 6 percent
Simple interest = 
P=8000, n=1 year and r=6
interest = 
Interest = 480 dollars
P= 10000, t=1, r=8%=0.08, n=2 for semiannually
Interest = 10816- 10000=816
Total interest = 
Answer: If you're looking for the value of x, it's 1.
Step-by-step explanation:
Add the numbers. x-10-2x+7=8+x-10-3x--->x-3-2x=8+x-10-3x
Combine like terms. x-3-2x=8+x-10-3x ---> -x-3=8+x-10-3x
Subtract the numbers.-x-3=8+x-10-3x---> -x-3=-2+x-3x
Combine like terms. -x-3=-2+-3x---> -x-3=-2-2x
Rearrange terms. -x-3=-2-2x---> -x-3=-2x-2
Hope that helps!
Answer:
D
Step-by-step explanation:
gradient is change in y/change in x
gradient of UV = 14-8/12+4=3/4
use equation y=mx+c where y is the y coordinate, m is the gradient, x is the x coordinate and c is the y intercept
use one of the coordinates of U or V, I'll use (4,8)
c is 5
the equation for UV is
insert each X coordinate given in the question to see if it gives the same y coordinate
when x is 20, y is also 20 so the answer is D
You can either use the inverse function theorem or compute the general derivative using implicit differentiation. The first method is slightly faster.
The IFT goes like this: if f(x) is invertible and f(a) = b, then finv(b) = a (where "finv" means "inverse of f").
By definition of inverse functions, we have
f(finv(x)) = finv(f(x)) = x
Differentiating both sides of the second equality with respect to x using the chain rule gives
finv'(f(x)) * f'(x) = 1
When x = a, we get
finv'(b) * f'(a) = 1
or
finv'(b) = 1/f'(a)
Now let f(x) = sin(x), which is invertible over the interval -π/2 ≤ x ≤ π/2. In the interval, we have sin(x) = √3/2 when x = π/3. We also have f'(x) = cos(x).
So we take a = π/3 and b = √3/2. Then
arcsin'(√3/2) = 1/cos(π/3) = 1/(1/2) = 2
