From the text you can derive the following equations:
(1) A = bh/2 = 8
(2) and h = b+6
Fill in h in (1):
b(b+6)/2 = 8 => b^2 + 6b = 16 with the quadratic formula or simply trying some values for b you can find b=2, so h=8.
Option B:
is the new equation
Explanation:
The given equation is ![$y=-\sqrt[3]{x}$](https://tex.z-dn.net/?f=%24y%3D-%5Csqrt%5B3%5D%7Bx%7D%24)
We need to find the new graph which is shifted 7 units up and 4 units right.
First, we shall shift the graph 7 units up.
The general formula to shift the graph b units up is given by

Thus, to shift the graph 7 units up, let us substitute
and
in the general formula, we have,
![y=$-\sqrt[3]{x}$+7](https://tex.z-dn.net/?f=y%3D%24-%5Csqrt%5B3%5D%7Bx%7D%24%2B7)
Now, we shall shift the graph 4 units right.
The general formula to shift the graph b units right is given by

Thus, to shift the graph 4 units right, let us substitute
and
in the above equation, we have,
![$y=-\sqrt[3]{x-4}+7$](https://tex.z-dn.net/?f=%24y%3D-%5Csqrt%5B3%5D%7Bx-4%7D%2B7%24)
Therefore, the new equation is ![$y=-\sqrt[3]{x-4}+7$](https://tex.z-dn.net/?f=%24y%3D-%5Csqrt%5B3%5D%7Bx-4%7D%2B7%24)
Therefore, Option B is the correct answer.
Consecutive even integers..x, x + 2, x + 4
x + (x + 2) + (x + 4) = 6216
3x + 6 = 6216
3x = 6216 - 6
3x = 6210
x = 6210/3
x = 2070
x + 2 = 2070 + 2 = 2072
x + 4 = 2070 + 4 = 2074 <===house 3
Answer:
16-(-2)/ -6-(-4)= 18/-2= -9
Step-by-step explanation:
y2-y1/ x2-x1
Answer: depends on the type of cracker
Step-by-step explanation: