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Oksi-84 [34.3K]
3 years ago
7

Good luck everyone if this is your last bit of school. :)

Mathematics
2 answers:
salantis [7]3 years ago
8 0

Answer:

Thnx Bro

U to

Step-by-step explanation:

I am Lyosha [343]3 years ago
5 0

Answer:

thanks good luck to u too

Step-by-step explanation:

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A baseball player had 4 hits in 8 games. At this rate, how many hits will the baseball player have in the next 28 games?
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14 hits

8 divided by 2 = 4 hits
So
28 divides by 2 = 14
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How to solve logarithmic equations as such
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\bf \textit{exponential form of a logarithm} \\\\ \log_a b=y \implies a^y= b\qquad\qquad a^y= b\implies \log_a b=y \\\\\\ \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \log_2(x-1)=\log_8(x^3-2x^2-2x+5) \\\\\\ \log_2(x-1)=\log_{2^3}(x^3-2x^2-2x+5) \\\\\\ \log_{2^3}(x^3-2x^2-2x+5)=\log_2(x-1) \\\\\\ \stackrel{\textit{writing this in exponential notation}}{(2^3)^{\log_2(x-1)}=x^3-2x^2-2x+5}\implies (2)^{3\log_2(x-1)}=x^3-2x^2-2x+5

\bf (2)^{\log_2[(x-1)^3]}=x^3-2x^2-2x+5\implies \stackrel{\textit{using the cancellation rule}}{(x-1)^3=x^3-2x^2-2x+5} \\\\\\ \stackrel{\textit{expanding the left-side}}{x^3-3x^2+3x-1}=x^3-2x^2-2x+5\implies 0=x^2-5x+6 \\\\\\ 0=(x-3)(x-2)\implies x= \begin{cases} 3\\ 2 \end{cases}

5 0
3 years ago
I need help with this. How does one make 4 DIFFERENT equations for the SAME four points.
vichka [17]

Answer:

You put a equal sign or if its one equation then put a addition or subtraction sign etc.

Step-by-step explanation:

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Last month, a car dealership sold 376 new cars.
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as per as I can think the answet will be 38

please give me brainliest if my answer is correct

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