So
eq=ellen's quarters
en=ellens's nickles
lq=lola's quarters
ln=lola's nickles
lq/2=eq or lq=2(eq)
2(ln)=en or ln=en/2
en+eq=$6.30 or 630 cents
en+6nickles=eq
so nickle=5 so
5*6=30
630-30=600
number of nicles=number of quarters of lola=600
nickle+quater=30
600/30=20
20 quarters
20+6=26 nickles
elen has 20 quarters and 26 nickles
20 times 2=40 quarters
26 divided by 2=13 nickles
lola has 40 quarters and 13 nickles
40 times 25=1000 cents in quarters
13 times 5=65 cents in nickles
1000+65=1065 cents or $10.65=lola's money
You get 1/4 a pint for 1 dollar. Because each pint is 4$,
<span>C. It has two real solutions.
The discriminant in solving a quadratic equation is b^2-4ac. If this is greater than zero it has two real solutions.</span>
There is nothing attached
Answer:
Step-by-step explanation:
When learning about commutative and associative properties, we learn that ...
a + b = b + a . . . . . addition is commutative
ab = ba . . . . . . . . . multiplication is commutative
But we also know that ...
a - b ≠ b - a . . . . . . subtraction is not commutative
a/b ≠ b/a . . . . . . . . division is not commutative
__
We also learn that ...
a + (b+c) = (a+b) +c . . . . addition is associative
a(bc) = (ab)c . . . . . multiplication is associative
And of course, ...
a - (b -c) ≠ (a -b) -c . . . . subtraction is not associative
a/(b/c) ≠ (a/b)/c . . . . . . . division is not associative
_____
However, you can use associative and commutative properties in problems involving subtraction and division if you write the expression properly:
a - (b - c) = a +(-(b -c)) = a +((-b) +c) = (a +(-b)) +c . . . . keeping the sign with the value makes it an addition problem, so the associative property can apply
(a/b)/c = (a(1/b))(1/c) = a(1/b·1/c) = writing the division as multiplication by a reciprocal makes it so the associative property can apply
