3 years ago

PLEASE HELP ME SO I CAN MOVE ON FROM THIS TOPIC

Mathematics

1 answer:

ExtremeBDS [4]3 years ago

4 0

Answer:

3rd option

Step-by-step explanation:

( $\frac{f}{g}$ )(x)

= $\frac{f(x)}{g(x)}$

= $\frac{2x^2-5x-3}{2x^2+5x+2}$ ← factorise numerator and denominator

= $\frac{(x-3)(2x+1)}{(x+2)(2x+1)}$ ← cancel (2x + 1) on numerator/ denominator

= $\frac{x-3}{x+2}$

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