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attashe74 [19]
3 years ago
7

20 POINTS!!!!!! please be correct or i will report I have to get this done now..

Mathematics
2 answers:
Setler79 [48]3 years ago
4 0

Answer:

1/4

Step-by-step explanation:

I put it into a calculator

iVinArrow [24]3 years ago
3 0

Answer:

1/4

Step-by-step explanation:

7/8 plus -2/3 is 5/24. Then you divided by 5/6 to get 1/4

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photoshop1234 [79]

Answer:

Area=91 ft^2

Step-by-step explanation:

Area=length*width

Area= 14*6.5

Area=91 ft^2

5 0
3 years ago
Another chart question that I don’t know
zloy xaker [14]

From birth to 5yo = 91,200

from 5 to 18yo = 167,000

therefore from birth to 18yo will cost 91,200 + 167,000 which is 258,200

Since the question says per year and thats the total cost of 18 years ( from 0 years to 18), we divide it by 18.

258,200 ÷ 18 = 14,344

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3 0
3 years ago
Find the slope(6,8) and (9,10)
USPshnik [31]

name the points

a=(x1,y1) b=(x2,y2)

a=(6,8) b=(9,10)

use the slope formula

m=\frac{y2-y1}{x2-x1}

replace

\begin{gathered} m=\frac{10-8}{9-6} \\ m=\frac{2}{3} \end{gathered}

answer= The slope is equal to 2/3

a=(9,10) b=(6,8)

using the formula

\begin{gathered} m=\frac{y2-y1}{x2-x1} \\ m=\frac{8-10}{6-9} \\ m=\frac{-2}{-3}=\frac{2}{3} \end{gathered}

slope will also be 2/3

5 0
1 year ago
Litter such as leaves falls to the forest floor, where the action of insects and bacteria initiates the decay process. Let A be
Travka [436]

Answer:

D = L/k

Step-by-step explanation:

Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is

dA/dt = in flow - out flow

Since litter falls at a constant rate of L  grams per square meter per year, in flow = L

Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow

So,

dA/dt = in flow - out flow

dA/dt = L - Ak

Separating the variables, we have

dA/(L - Ak) = dt

Integrating, we have

∫-kdA/-k(L - Ak) = ∫dt

1/k∫-kdA/(L - Ak) = ∫dt

1/k㏑(L - Ak) = t + C

㏑(L - Ak) = kt + kC

㏑(L - Ak) = kt + C'      (C' = kC)

taking exponents of both sides, we have

L - Ak = e^{kt + C'} \\L - Ak = e^{kt}e^{C'}\\L - Ak = C"e^{kt}      (C" = e^{C'} )\\Ak = L - C"e^{kt}\\A = \frac{L}{k}  - \frac{C"}{k} e^{kt}

When t = 0, A(0) = 0 (since the forest floor is initially clear)

A = \frac{L}{k}  - \frac{C"}{k} e^{kt}\\0 = \frac{L}{k}  - \frac{C"}{k} e^{k0}\\0 = \frac{L}{k}  - \frac{C"}{k} e^{0}\\\frac{L}{k}  = \frac{C"}{k} \\C" = L

A = \frac{L}{k}  - \frac{L}{k} e^{kt}

So, D = R - A =

D = \frac{L}{k} - \frac{L}{k}  - \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{kt}

when t = 0(at initial time), the initial value of D =

D = \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{k0}\\D = \frac{L}{k} e^{0}\\D = \frac{L}{k}

4 0
3 years ago
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Geometric sequence is a sequence of numbers that have a common ratio between them.
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