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kvv77 [185]
3 years ago
9

I need help can someone figure these out?

Mathematics
2 answers:
maw [93]3 years ago
4 0

Answer:the 2nd one is 30000 divided by 2000 is 15

Step-by-step explanation: so 15 minutes til they crash the plane

Pachacha [2.7K]3 years ago
3 0

Answer:

1) y= 25x+50

2) y= -2,000x+30,000

3) y= 1.5x+5

Step-by-step explanation:

In each equation, there is a set amount (50 dollars, 30,000 feet, and 5 centimeters) and an amount that is influenced by another variable such as time(25 dollars, 2,000 feet, 1.5 centimeters). Hope this helped :)

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What is the probability that in a randomly selected game, the first goal is scored in less than 4 minutes?
kogti [31]

Based on the characteristics of the distribution, the probability that the first goal is scored in less than 4 minutes is 0.

<h3>What is the probability?</h3>

For us to be able to calculate the probability that the first goal is scored in less than 4 minutes, the distribution needs to satisfy the requirements of the Central Limit Theorem(CLT).

Based on the fact that the distribution here is extremely right skewed, then it does not satisfy the requirements of CLT so the probability is 0.

First part of question:

The distribution of the time it takes for the first goal to be scored in a hockey game is known to be extremely right skewed with population mean 12 minutes and population standard deviation 8 minutes.

Find out more on the requirements of the Central Limit Theorem at brainly.com/question/18403552

#SPJ4

4 0
1 year ago
A car insurance company has high-risk, medium-risk, and low-risk clients, who have, respectively, probabilities .04, .02, and .0
Paha777 [63]

Answer:

(a) 0.983

(b) 0.353 or 35.3%

(c) 0.604 or 60.4%

Step-by-step explanation:

a) The probability of a random client does not file a claim is equal to the sum of:

1) the probability of a client being high risk and does not file a claim = P(hr)*(1-P(c_hr))

2) the probability of a client being medium risk and does not file a claim = P(mr)*(1-P(c_mr))

and

3) the probability of a client being low risk and does not file a claim = P(lr)*(1-P(c_lr))

P(not claim) = P(hr)*(1-P(c_hr))+P(mr)*(1-P(c_mr))+P(lr)*(1-P(c_lr))

P(not claim) = 0.15*(1-0.04)+0.25*(1-0.02)+0.6*(1-0.01)

P(not claim) = 0.15*0.96+0.25*0.98+0.6*0.99 = 0.983

(b) To know the proportion of claims that come from high risk clients we need to know the total expected claims in every category:

Claims expected by high risk clients = P(c_hr)*P(hr) = 0.04*0.15 = 0.006 claims/client

Claims expected by medium risk clients = P(c_mr)*P(mr) = 0.02*0.25 = 0.005 claims/client

Claims expected by low risk clients = P(c_lr)*P(lr) = 0.01*0.60 = 0.006 claims/client

The proportion of claims done by high risk clients is

Claims by HR clients / Total claims expected = 0.006 / (0.006+0.005+0.006) =  0.006 / 0.017 = 0.3529 or 35,3%

(c)  The probability of being a client of a particular category and who don't file a claim is:

1) High risk: 0.15*(1-0.04) = 0.144

2) Medium risk: 0.25*(1-0.02) =  0.245

3) Low risk: 0.6*(1-0.01) = 0.594

The probability that a random client who didn't file a claim is low- risk can be calculated as:

Probability of being low risk and don't file a claim / Probability of not filing a claim

P(LR&not claim)/P(not claim) = 0.594 / (0.144+0.245+0.594)

P(LR&not claim)/P(not claim) = 0.594 /  0.983 = 0.604 or 60.4%

6 0
3 years ago
Adam divides 32/8032. In which place should he write the first digit of the quotient?
kow [346]

Answer:

We have a quotient between a 2 digit number and a 4 digit number.

The usual rule for this type of problems is:

If the denominator has n more digits than the numerator, then the first digit will be in the nth position at the right of the decimal point.

If also, the denominator is larger than the numerator times 10^n, then the decimal will be moved another place to the right.

For example, if we divide 10 by 100 we have:

10/100

The denominator has one more digit than the numerator, then n = 1.

this means that the first digit of the quotient, will be on the first place at the left of the decimal point.

We can solve the quotient to get:

10/100 = 0.1

And, as we predicted, the first decimal is in the first place.

Now, with our quotient we have:

32/8032

n = 2.

and:

32*10^n = 3200

The denominator is larger than this, then we will move the first decimal to another place to the right.

Then we should expect to have the first decimal in the third place after the decimal point.

We can solve the quotient to get:

32/8032 = 0.0039

As we expected.

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