Step-by-step explanation:
they're is a neat little trick.
but first of all, "roots" means the 0 solutions of the equation. like
ax² + bx + c = 0
there are 2 solutions for x to make the whole expression equal 0.
these are the "roots".
now to the little trick :
when is a multiplication resulting in 0 ?
when at least one of the factors is 0.
and any quadratic expression can be written as multiplication of 2 factors. like
c(x - a)(x - b) = cx² - cax - cbx + cab
what are the "roots" or 0 points ?
either
c = 0
x - a = 0 | x = a
x - b = 0 | x = b
the leading coefficient = 3.
that means nothing else than c = 3.
root = 1 means (x - 1) is one factor.
root = -5 means (x + 5) is the other factor.
so, we have
3(x - 1)(x + 5) = 3x² + 12x - 15
and the equation is
3x² + 12x - 15 = 0
or
3x² + 12x = 15
<h2>Question :</h2>
<em>Write the equation of a line that is perpendicular to the given line and that passes through the given point. y=2/3x+9 m (–6, 5)</em>
<h2>Answer :</h2>
<em>y = -3/2x - 4 </em>
<h2>Explanation :</h2>
y = mx + c
*m = gradien
•>looking for gradients
y=2/3x+9
m1 = 2/3
m2 = -3/2
•>line equation (-6,5)
y - y1 = m(x - x1)
y - 5 = -3/2(x - (-6))
y - 5 = -3/2(x + 6)
y - 5 = -3/2 - 9
y = -3/2x - 9 + 5
y = -3/2x - 4
We have that
smaller figure
ha=8.7
ra=1.6
larger figure
hb=10.44
rb=1.92
ha/hb=8.7/10.44----> 0.83
ra/rb=1.6/1.92-------> 0.83
ratio smaller figure to the larger figure
1.6/1.92-------> divided by 1.6 both members[1.6/1.6]/[1.92/1.6]-------> 1/1.2
the ratio ha/hb is equal to the ratio ra/rb
so
the smaller figure and the larger figure are similar
and
the ratio smaller figure to the larger figure is equal to----> 1/1.2
the answer is
the option yes 1/1.2
Answer:
Less than
Step-by-step explanation:
Its less than because the angle of LS is 98 while MS is 95, so LS is longer
Answer: graph D
<u>Step-by-step explanation:</u>
graph A) The equation is y = x
graph B) The equation is y = -x² + 2
graph C) The equation is x = y²
graph D) The equation is y = 2
Which equation does not have an "x" in it? <em>D</em>
Therefore, the y-value is not dependent on an x-value.
