Answer:
yes
no
yes
no
Step-by-step explanation:
i think its right
Answer:
Step-by-step explanation:
your equation shown above is set up incorrectly in order to solve this i need the right equation you must plug in each number to q to find the right solution
Ahhh I think that is cheating?
Soz I know the anaswer but I cant tell you have to do by your self to learn you can't always ask for answers :<
Answer:
2x+w/5
Step-by-step explanation:
(2*x)+(w/5)
2x +w/5
• First way to solve:
We'll manipulate the expression of the equation:

If we have y=0:

Then, the function has one real zero (x=3) and two imaginary zeros (4i and -4i).
Answer: B
• Second way to solve:
The degree of the function is 3. So, the function has 3 complex zeros.
Since the coefficients of the function are reals, the imaginary roots are in a even number (a imaginary number and its conjugated)
The function "has only one non-repeated x-intercept", then there is only one real zero.
The number of zeros is 3 and there is 1 real zero. So, there are 2 imaginary zeros.
Answer: B.