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2 years ago

A B C D Help me out

Mathematics

1 answer:

aleksklad [387]2 years ago

6 0

Answer:

2x^2 + 3/2x -5

Step-by-step explanation:

f(x) = x/2 -2

g(x) = 2x^2 +x -3

f(x)+ g(x) = x/2 -2+ 2x^2 +x -3

Combine like terms

= 2x^2 + 3/2x -5

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Richard walks every day for exercise at a rate of 1 kilometer every 12 min. At this rate ,how many meters can Richard walk in a

garik1379 [7]

60 minutes in an hour
60÷12=5
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therefore, 5000 meters

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Answer:

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3 years ago

Assume that a company hires employees on Mondays, Tuesdays, or Wednesdays with equal likelihood.a. If two different employees ar

horsena [70]

Answer:

$P(A) = \frac{1}{9}$

$P(B) = \frac{1}{3}$

$P(C) = \frac{1}{729}$

Step-by-step explanation:

We know that:

Only employees are hired during the first 3 days of the week with equal probability.

2 employees are selected at random.

So:

A. The probability that an employee has been hired on a Monday is:

$P(M) = \frac{1}{3}$ .

If we call P(A) the probability that 2 employees have been hired on a Monday, then:

$P(A) =P(M\ and\ M)\\\\P(A)=( \frac{1}{3})(\frac{1}{3})\\\\P(A) = \frac{1}{9}$

B. We now look for the probability that two selected employees have been hired on the same day of the week.

The probability that both are hired on a Monday, for example, we know is $P(A) = \frac{1}{9}$ . We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.

$P(B) = \frac{1}{9} + \frac{1}{9} + \frac{1}{9}\\\\P(B) = \frac{1}{3}$ .

C. If the probability that two people have been hired on a specific day of the week is $3(\frac{1}{3}) ^ 2$ , then the probability that 7 people have been hired on the same day is: