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Misha Larkins [42]
3 years ago
5

8+–5+–7w+6w answer- please-

Mathematics
2 answers:
Scorpion4ik [409]3 years ago
7 0
8-5-7w+6w

Combine Like Terms

3-w
Damm [24]3 years ago
4 0

Answer:

3-w

Step-by-step explanation:

8+(-5)+(-7w)+6w

8-5-7w+6w

3-7w+6w

3-w

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Let h(x) = (g o f)(x) = sqrt{x+3}
Debora [2.8K]
I am assuming you meant to write the following options

A. f(x)=x+3; g(x)=√x
B. f(x)=x; g(x)=x+3
C. f(x)=√x; g(x)=x+3
D. f(x)=3x; g(x)=√x

You need to find a fucntion f(x) that once evaluated in g(x) gives us as a result h(x)

h(x) =  g(f(x))

Looking at the options, the answer is A.

g(f(x)) = sqrt(f(x)) = sqrt (x + 3) = h(x)
8 0
4 years ago
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Explain why f(x) = x^2+4x+3/x^2-x-2 is not continuous at x = -1.
liberstina [14]

Answer:

The value of x = -1 makes the denominator of the function equal to zero. That is why this value is not included in the domain of f(x)

Step-by-step explanation:

We have the following expression

f(x) = \frac{x^2+4x+3}{x^2-x-2}

Since the division between zero is not defined then the function f(x) can not include the values of x that make the denominator of the function zero.

Now we search that values of x make 0 the denominator factoring the polynomial x^2-x-2

We need two numbers that when adding them get as a result -1 and when multiplying those numbers, obtain -2 as a result.

These numbers are -2 and 1

Then the factors are:

(x-2) (x + 1)

We do the same with the numerator

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We need two numbers that when adding them get as a result 4 and when multiplying those numbers, obtain 3 as a result.

These numbers are 3 and 1

Then the factors are:

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Therefore

f(x) = \frac{(x+3)(x+1)}{(x-2)(x+1)}

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So since x = -1 is not included in the domain the function has a discontinuity in x = -1

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3 years ago
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Rus_ich [418]
For the first one it might be 26? i’m not so sure
8 0
3 years ago
Please help!!!!!!!!!
kotykmax [81]

10+6+9+13+7= 45

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