Given p ll r and m angle 8=119, find m angle 11

Given the following winning percentages of the teams in a league (for a single year) compute the within-season standard deviatio

Masja [62]

Answer:

(b) 0.251

Step-by-step explanation:

1. Standard deviation equation:

$SD=\sqrt{\frac{\sum\limits^N_i {(x_{i}-X)^{2} } }{N} }$

Where X is the mean of the data, and N the amount of data. Then, N=5

2. Estimate the Mean:

$X=\frac{0.750+0.750+0.200+0.600+0.200}{5}=\frac{2.5}{5}=0.5\\$

3. Caclulate Standard deviation:

$SD=\sqrt{\frac{{(0.750-0.500)^{2}+(0.750-0.500)^{2}+(0.200-0.500)^{2}+(0.600-0.500)^{2}+(0.200-0.500)^{2} } }{5} }$

$SD=\sqrt{\frac{0.315}{5} }=\sqrt{0.063}\\SD=0.251$

7 0

2 years ago

Is it enough to plot two points to see a pattern for a graph ? Explain.

devlian [24]

No, the least amount of points you can do on a graph to see the pattern is 3 because than you can get a better line for your graph to see what kind of pattern your graph is.

6 0

2 years ago

Read 2 more answers

i need this im confused on it. i would appreciate it if someone could help me out!! u have to show all ur work.

Kazeer [188]

Answer:

see below

Step-by-step explanation:

$1) -4x + 9x = 5x\\\\2) 6y -8y = -2y\\\\3) -7x+x = -6x\\\\4) 9y-y = 8y\\\\5) -5x-5x = -10x\\\\6) 3y-7y = -4y\\\\7) -x-8x+7 = -9x +7\\\\8) y-2y -3 = -y -3\\\\9) 5+5x-4x = 5 + x\\\\10) 3y-6 +7y-4y = 6y -6\\\\11) -9x-5-8+x = -13 -8x\\\\12) 6-y+5y-6y = 6 -2y\\\\13) 3x-8y+2x-5-5y = 5x -13y -5\\\\14)-9x +3 +2x-9y-8 = -7x -9y -5\\\\15) 5 +6x -3y +x +8y = 7x +5y+5\\\\16) -4x -4 +x -2y +7x = 4x -2y -4\\\\17) -8x +7y-x-6y+4x = -5x +y\\\\18) x+5-2x+3y-y=2y-x+5\\\\19) 9x-3y+7-4x+y-3 = 5x-2y+4\\\\$

$20) -x-3+5x+6y+8x-9\\\\21) 4x-4-8y+8-5x+1 = -x-8y+5\\\\22) 3x-x+6y-4x-y = -2x+5y\\\\23) 2x+2y-x-y-7+5y = x+6y-7\\\\24) 6x-8x-4y -x+5y-2y = -3x-y\\\\$

5 0

2 years ago

How many solutions does a triangle with side lengths a = 4, A = 112º and b =<br>9 have?

Ainat [17]

Answer:

This case has NO solutions.

Step-by-step explanation:

Notice that you are in a case of an obtuse triangle (one of its angles is larger than 90 degrees), the side opposite to the obtuse triangle is shorter than the side adjacent to the angle, so no actual triangle can be formed.

This can be found by simply trying to apply the Law of Sines to solve for the value of angle "B" opposite to side "b":

$\frac{sin(A)}{a} =\frac{sin(B)}{b}\\sin(B)=\frac{b\,sin(A)}{a}\\sin(B)=\frac{9\,sin(112^o)}{4}\\\\sin(B)=2.086$

As shown above, we get an impossible mathematical condition (also call an absurd), since the sine of an angle cannot give a value larger than 1 (one).

Therefore, there is no angle we can find to build a triangle with the given data.

7 0

2 years ago

A baker uses a coffee mug with a diameter of 8cm to cut out circular cookies from a big sheet of cookie dough. What is the area

kodGreya [7K]

Diameter = 8 cm

radius = diameter/2 = 4 cm

A = pi * r^2

A = pi * (4 cm)^2

A = 16pi cm^2

4 0

2 years ago

Given p ll r and m angle 8=119, find m angle 11​

Given p ll r and m angle 8=119, find m angle 11