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2 years ago

Estimate the quotient of 1,483 ÷ 4.

Mathematics

1 answer:

nikklg [1K]2 years ago

6 0

Your answer is 370.75

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I need help on .5 and .6

Dovator [93]

5. 44 (forty four)
6. 58

8 0

3 years ago

I've tried solving this but I'm stuck -8=2/x

USPshnik [31]

Answer:

-0.25

Step-by-step explanation:

-8= 2/x

multiply both sides by x -> -8x =2

divide both sides by -8 -> x=2/-8

Ans= -1/4 = -0.25

5 0

3 years ago

Read 2 more answers

(7x - 1) + (-x - 2) in simplest terms

ch4aika [34]

Answer:

6x-3

Step-by-step explanation:

6 0

2 years ago

Beaker A contains 1 liter which is 30 percent oil and the rest is vinegar, thoroughly mixed up. Beaker B contains 2 liters which

alekssr [168]

Answer:

1.25 liters of oil

Step-by-step explanation:

Volume in Beaker A = 1 L

Volume of Oil in Beaker A = 1*0.3 = 0.3 L

Volume of Vinegar in Beaker A = 1*0.7 = 0.7 L

Volume in Beaker B = 2 L

Volume of Oil in Beaker B = 2*0.4 = 0.8 L

Volume of Vinegar in Beaker B = 1*0.6 = 1.2 L

If half of the contents of B are poured into A and assuming a homogeneous mixture, the new volumes of oil (Voa) and vinegar (Vva) in beaker A are:

$V_{oa} = 0.3+\frac{0.8}{2} \\V_{oa} = 0.7 \\V_{va} = 0.7+\frac{1.2}{2} \\V_{va} = 1.3$

The amount of oil needed to be added to beaker A in order to produce a mixture which is 60 percent oil (Vomix) is given by:

$0.6*V_{total} = V_{oa} +V_{omix}\\0.6*(V_{va}+V_{oa} +V_{omix}) = V_{oa} +V_{omix}\\0.6*(1.3+0.7+V_{omix})=0.7+V_{omix}\\V_{omix}=\frac{0.5}{0.4} \\V_{omix}=1.25 \ L$

1.25 liters of oil are needed.

6 0

3 years ago

Thanks, brainliest, and 5 stars!!

frez [133]

I hope this helps its step 2 gl

4 0

3 years ago