Answer: y = 2000x + 89000
Step-by-step explanation:
Given that;
initial purchase amount = $89,000
price after 6 years = $ 101,000
years = 6
now
slope = ( 101000 - 89000) / 6
slope = 12000 / 6
slope = 2000
therefore the linear equation that models the value of the house after x years will be;
y = 2000x + 89000
To solve each question, all you've got to do is add the two numbers together and then graph the result on the number line.
1.) -3 +(-1.5)
Add 3 to -1.5. It would be the same as subtracting 1.5 from -3(-3 - 1.5)
Final Answer: -4.5<span>
Or, since you are using a number line, start on -3 and go left 1.5 units and you will land on the -4.5 point. You go to the left because you are adding a negative number..
</span>
2.) 1.5+3.5
Add<span>
Final Answer: 5
</span>Or, since you are using a number line, start on 1.5 and go to the right 3.5 and you will land on 5. You go to the right because you are adding a positive number.<span>
</span>3.) 1/4 + 1/2
Multiply 1/2 by 2 to make both fractions have the same denominator
1/4 + 2/4
Add<span>
Final Answer: 3/4
</span>Or, since you are using a number line, start on 1/4 and go up 2/4 and you will land on 3/4 as the result.<span>
</span>4.) -1 1/2 + (-1 1/2)
Add -1 1/2 to -1 1/2. This would be the same as subtracting 1 1/2 from -1 1/2(-1 1/2 - 1 1/2)<span>
Final Answer: -3
</span><span>Or, since you are using a number line, start on -1 1/2 and go to the left 1 1/2 and you will land on the -3 point.</span>
Algebraically, that would be 5n - 11 = 24
this is the answer to this question - Two weather tracking stations are on the equator 146 miles apart. A weather balloon is located on a bearing of N 35°E from the western station and on a bearing of N 23°E from the eastern station. How far is the balloon from the western station?
Answer:
Reasons:
The given parameters are;
Distance between the two stations = 146 miles
Location of the weather balloon from the Western station = N35°E
Location of the weather balloon from the Eastern station = N23°E
The location of the station = On the equator
Required:
The distance of the balloon from the Western station
Solution:
- The angle formed between the horizontal, and the line from the Western station
to the balloon = 90° - 35° = 55°
- The angle formed between the horizontal, and the line from the Eastern station
to the balloon = 90° + 23° = 113°
The angle at the vertex of the triangle formed by the balloon and the two stations is 180° - (55 + 113)° = 12°
By sine rule,
Distance from balloon to western station = 146/sin(12 dg) = Distance from balloon to western station/sin(113 dg)
Therefore;
Distance from balloon to western station = 146/sin(12 dg) x sin(113 dg) ~ 646.4
Step-by-step explanation:
Answer:
Not going to lie I can only give you a guess which is -72 sorry if that didn't do much.
Step-by-step explanation:
