How many 2/3 are in six

Find the measure of angle 1.

jasenka [17]

Answer:

∠ 1 = 104°

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ 1 is an exterior angle of the triangle , then

∠ 1 = 36° + 68° = 104°

8 0

3 years ago

Davon had 3/4 of a bag of popcorn. His friends are half of his popcorn. What fraction of the whole bag of popcorn did Davon's fr

Nikolay [14]

His friends ate 1/2 of 3/4..." of " means multiply
1/2 * 3/4 = 3/8

so his friends ate 3/8 of the bag of popcorn

6 0

3 years ago

Read 2 more answers

Josh is twenty-five years older than his son Carlos. In ten years Josh will be twice as old as Carlos. How old is Carlos now?

Nimfa-mama [501]

15, hope this helps!

3 0

3 years ago

On monday kayla borrowed $15 from his mom on Tuesday he borrowed another $10 what is the equation to show how much money kayla b

harina [27]

Answer:

$35

Step-by-step explanation:

Monday: $15

Tuesday: $10

15+10=35

$35 total

6 0

3 years ago

Read 2 more answers

Your company is considering offering 900 employees the opportunity to transfer to its new headquarters in Ottawa and, as personn

Tresset [83]

Answer:

a) $P(100M) = \frac{100C100*1100C800}{1200C900}$

b) $P(1M) = \frac{100C1*1199C899}{1200C900}$

Step-by-step explanation:

Extract information from question:

Manager = M = 100

Factory Workers = FW = 200

Miscellaneous Staff = MS = 900

Total Workers = 1200

Moving Workers = 900

'Combinations' are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations the formula below is used:

$nCr=\frac{n!}{r!(n-r)!}$

where 'n' is the total number of items

'r' is the number of items being chosen at a time

The '!' is the factorial function which is the product of all integers equal to and less than the given integer.

Combinations can be calculated manually using the formula above or by using the nCr function on a scientific calculator.

Part a)

Combinations of all 100 managers being selected

$C = nCr=\frac{n!}{r!(n-r)!}$

$C(100M) = 100C100$

Combinations of 800 of factory workers and miscellaneous staff being selected out of 1100 remaining staff

$C = nCr=\frac{n!}{r!(n-r)!}$

$C(800FW/MS) = 1100C800$

Total possible unspecified combinations of 900 staff being selected out of 1200 total staff

$C = nCr=\frac{n!}{r!(n-r)!}$

$C(900M/FW/MS) = 1200C900$

Probability of all 100 managers being selected:

$P(100M) = \frac{100C100*1100C800}{1200C900}$

Part b)

Combinations of 1 out of 100 managers being selected

$C = nCr=\frac{n!}{r!(n-r)!}$

$C(1M) = 100C1$

Combinations of 899 of managers, factory workers and miscellaneous staff being selected out of 1199 remaining staff

$C = nCr=\frac{n!}{r!(n-r)!}$

$C(899M/FW/MS) = 1199C899$

Total possible unspecified combinations of 900 staff being selected out of 1200 total staff

$C = nCr=\frac{n!}{r!(n-r)!}$

$C(900M/FW/MS) = 1200C900$

Probability of being the 1 manager being selected:

$P(1M) = \frac{100C1*1199C899}{1200C900}$

3 0

3 years ago