PLEASE PLEASE HELP ME!!
1 answer:
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Answer:
a) Braxton's initial investment is equals to (=) Pam's initial investment.
b)The interest on Braxton's account is less than (< ) the interest on Pam's
account.
Step-by-step explanation:
Given - Braxton has money in a savings account. The equation
B = can be used to calculate the amount of money
in dollars, B, Braxton has in his account after t years since opening
the account. Pam also has money in a savings account. The
equation, P= can be used to calculate the amount of
money in dollars, P, Pam has in her account after t years since
opening the account.
To find - a) Braxton's initial investment ..........Pam's initial investment.
b) The interest on Braxton's account .....the interest on Pam's
account.
Proof -
As given, Broxton equation is -
Pam equation is -
Now,
a.)
For initial investment , Put t = 0
⇒B =
P =
We can see that for t = 0
Initial investment of Braxton = Initial investment of Pam
⇒Braxton's Initial investment = Pam's initial investment.
b.)
For the interest,
As we have not given any time period for which the interest has to be find.
So , let the time period , t = 5 years
Therefore,
B =
P =
Now,
Interest on Braxton's account = 927.42 - 800 = 127.42 ≈ 127
Interest on Pam's account = 973.32 - 800 = 173.32 ≈ 173
∴ we get
The interest on Braxton's account is less than the interest on Pam's account.
The median is the vertical line in the box
and the interquartile range is the length of the box itself
So the answer would be B as its median is greater than 80 and it has the large <span>interquartile range...
</span>
and the interquartile range is the length of the box itself
So the answer would be B as its median is greater than 80 and it has the large <span>interquartile range...
</span>
I hope that helps!