Question

Two linear equations are represented by using the tables below.

Answer 1

Answer:

(–3, –2)

Step-by-step explanation:

A linear equation is an equation in the form y = mx + b, where m is the slope of the line and b is the y intercept.

Equation A is represented by the points:

x:    -5      -2        0          1

y:    -4       -1         1           2

Equation A can be gotten by picking any two pair of points. Let us use (-5, -4) and (0, 1). We use this formula:

$y- y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-(-4)=\frac{1-(-4)}{0-(-5)} (x-(-5))\\\\y +4=x+5\\\\y=x+1$

Equation B is represented by the points:

x:    -6      -3        3          6

y:    -4       -2         2          4

Equation B can be gotten by picking any two pair of points. Let us use (-6, -4) and (3, 2). We use this formula:

$y- y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-(-4)=\frac{2-(-4)}{3-(-5)} (x-(-6))\\\\y +4=\frac{2}{3}( x+6)\\\\y+4=\frac{2}{3} x+4\\\\y=\frac{2}{3}x$

The solution to the system of equations is gotten by solving y = x + 1 and y = (2/3)x simultaneously.

Substitute y = (2/3)x in y = x + 1:

(2/3)x = x + 1

2x = 3x + 3

x = -3

Put x = -3 in y = (2/3)x

y = (2/3) (-3) = -2

Hence (-3, -2) is the solution

Answer 2

Answer:

(-3,-2)

Step-by-step explanation: