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mr_godi [17]
2 years ago
6

5x-2y=15 2x+6y=-11 solve by substitution or equal values method

Mathematics
1 answer:
g100num [7]2 years ago
5 0

Answer:

Point form -

(2-\frac{5}{2})

Equation form -

x=2, y=-\frac{5}{2}

Step-by-step explanation:

if you have any questions feel free to ask

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I need help with this question​
4vir4ik [10]

Answer:

y = 3

Step-by-step explanation:

y/9 = 2/6

y/9 = 1/3 (dividing by 2in both numerator and denominator.)

CROSS MULTIPLYING WE GET

3y = 9*1

3y = 9

y = 3

4 0
2 years ago
Please help<br><br> What is the measure of ∠c?
malfutka [58]
It’s 56 bc a straight line = 180 so 180-124=56
5 0
3 years ago
Please help me! I'm spending 50 points on this question and my last two questions never even got answered!
Verdich [7]

Answer:

C.

Step-by-step explanation:

Domain is only affected if certain values can make the result something that either doesn't make sense or is an error. In your situation, it wants you to find the domain of f/g, which is a fraction. The only rule we have for fractions regarding domain is that we simply can't divide by zero, to find the domain for any fraction with variables in the denominator, what I do is take the denominator, set it equal to 0, and solve for x.

So, if we're taking f/g, we have:

\frac{3x^2 + x^4 + 2}{4x - 3}

4x - 3 makes up our denominator, the bottom part of the fraction. So

4x - 3 = 0

4x = 3

x = 3/4

So the denominator is equal to zero when x is equal to 3/4. This would produce an error in any calculator because you can't divide by zero. The domain here is all real numbers except for 3/4.

(For future problems, the only thing to look out for is if your numerator, the top part of the fraction, factors into something that cancels with the bottom. In that case, it wouldn't affect domain because you aren't actually dividing by anything. For example:

\frac{x^2 - 4}{x-2}

If we factor the top, we see that x^2 - 4 = (x - 2)(x + 2). In this case, we have (x - 2) in both the top and bottom of the fraction, so it cancels out, and from there nothing else is restricting our domain. It would be all real numbers in a case like that.)

8 0
3 years ago
Find the domain<br><br><img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Csqrt%7B3x%20%2B%205%7D%20" id="TexFormula1" title="y =
sveticcg [70]
y=\sqrt{3x+5}\\\\The\ domain:\\\\3x+5\geq0\ \ \ |-5\\\\3x\geq-5\ \ \ |:3\\\\x\geq-\dfrac{5}{3}\to x\in\left[-\dfrac{5}{3};\ \infty\right)
6 0
2 years ago
Read 2 more answers
How can I can the Graphing the function
laiz [17]

in short, you simply pick a few random "x" values, to get the "y", and that's your point, for example say x = 2, then y = -(2)² - 4 => y = -8, that gives us the point of (2, -8), and so on.


we can start off by finding the vertex, the U-turn of the graph, and then just pick a point to its left side and a point to its right side, and we can get the vertex of that by


\bf y=-4x^2-4\implies y=-4x^2+0x-4 \\\\[-0.35em] ~\dotfill\\\\ \textit{vertex of a vertical parabola, using coefficients} \\\\ y=\stackrel{\stackrel{a}{\downarrow }}{-4}x^2\stackrel{\stackrel{b}{\downarrow }}{+0}x\stackrel{\stackrel{c}{\downarrow }}{-4} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{0}{2(-4)}~,~-4-\cfrac{0}{4(-4)} \right)\implies (0~,~-4-0)\implies (0,-4)


and since it's a vertical parabola, the axis of symmetry comes from the x-coordinate of the vertex, namely x = 0, check the picture below.

6 0
3 years ago
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