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RUDIKE [14]
3 years ago
7

PLEASE HELPPP ILL GIVE BRAINLIESTTTT!!!!

Mathematics
1 answer:
Travka [436]3 years ago
7 0

Answer:

Isosceles triangle, <A=22°, <B=136°, <C=22°

Step-by-step explanation:

Look in the file :) Promise its safe and I'm not a bot.

AB and BC are legs of the triangle and AC is called the base of the triangle, <A and <C are acute angles while <B is an obtuse angle.

Have a nice day! :)

-Vana

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Solve pls branliest.
galina1969 [7]

Answer:

1. no. 2. yes. 3. no. 4. yes. 5. yes.

Step-by-step explanation:i'll explain how to identify integers.

The integers are ..., -4, -3, -2, -1, 0, 1, 2, 3, 4, ... -- all the whole numbers and their opposites (the positive whole numbers, the negative whole numbers, and zero). Fractions and decimals are not integers. For example, -5 is an integer but not a whole number or a natural number. ... Integers are numbers that do not have a fractional part, including positive and negative numbers and zero. Whole numbers are positive integers and zero. Natural numbers are positive integers and are sometimes called counting numbers. tell me if you need me to explain more.

7 0
2 years ago
How would u use commutative property to solve 2x+7+2x. PLEASE HELP MEE!!!<br> 30 POINTS!
Mkey [24]

Answer:

2x +7 +2x = 4x +7

Step-by-step explanation:

7 0
2 years ago
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Choose the function that the graph represents
gayaneshka [121]

Answer:

Where are the functions and the graph?

Step-by-step explanation:


6 0
3 years ago
Verify that the roots of 5x²- 6x -2 = 0 are <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%20%2B%20%5Csqrt%7B19%7D%20%7D%7B5%7D%2
Mice21 [21]

Answer:

Proof below.

Step-by-step explanation:

<u>Quadratic Formula</u>

x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0

<u>Given quadratic equation</u>:

5x^2-6x-2=0

<u>Define the variables</u>:

  • a = 5
  • b = -6
  • c = -2

<u>Substitute</u> the defined variables into the quadratic formula and <u>solve for x</u>:

\implies x=\dfrac{-(-6) \pm \sqrt{(-6)^2-4(5)(-2)}}{2(5)}

\implies x=\dfrac{6 \pm \sqrt{36+40}}{10}

\implies x=\dfrac{6 \pm \sqrt{76}}{10}

\implies x=\dfrac{6 \pm \sqrt{4 \cdot 19}}{10}

\implies x=\dfrac{6 \pm \sqrt{4}\sqrt{19}}{10}

\implies x=\dfrac{6 \pm2\sqrt{19}}{10}

\implies x=\dfrac{3 \pm \sqrt{19}}{5}

Therefore, the exact solutions to the given <u>quadratic equation</u> are:

x=\dfrac{3 + \sqrt{19}}{5} \:\textsf{ and }\:x=\dfrac{3 - \sqrt{19}}{5}

Learn more about the quadratic formula here:

brainly.com/question/28105589

brainly.com/question/27953354

3 0
1 year ago
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A 15 ounce alloy containing 30% gold was mixed with an alloy containing 5% gold to get an alloy containing 20% gold. How many ou
Studentka2010 [4]

Answer:

4.5 % alloy

Step-by-step explanation:

Let x = amt of 30% alloy

The resulting total is to be 25 oz, therefore:

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x = 3.75%2F.25

x = 15 oz of 30% alloy required

then

25-15 = 10 oz of 5% alloy:

Check solution

.30(15) + .05(10) = .20(25)

4.5 + .5 = 5

4 0
3 years ago
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