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Wewaii [24]
3 years ago
11

Which statement is true about the graphed function?

Mathematics
1 answer:
strojnjashka [21]3 years ago
3 0
Is there more to it?
You might be interested in
Consider these three numbers expressed in scientific notation 2.4 x10^4 , 6.3 x10^5 , and 9.6 x10^7
____ [38]
I considered them, but if you wanted them evaluated, here you go
24,000
630,000
96,000,000
8 0
3 years ago
What is the following product? (5√2-4√3)(5√2-4√3)
Galina-37 [17]

Step-by-step explanation:

(5√2-4√3)(5√2-4√3)=

(5√2-4√3)^2=(5√2)^2+(4√3)^2-2(5√2)(4√3)

=25*2+16*3-10√2*4√3

=50+48-10√2*4√3

=98-10√2*4√3 is the answer

6 0
3 years ago
Squad root of 130 by using the Babylonian method. Let 11.5 be initial.
tangare [24]


The Babylonian method for approximating square roots is the recursive method given by:

Given:

x0≈k−−√
x
0
≈
k


Then:

xn+1=x2n+k2xn
x
n
+
1
=
x
n
2
+
k
2
x
n


where k
k
is the number for which we are approximating the square root.

So, armed with this formula, let's now answer the given questions:

1.) Fill in the missing info in the problem to find square root 130 by using the Babylonian method. Let 11.5 be your initial guess.

We will use 15 digits of precision here since it is not stated how many iterations to carry out:

x0=11.5
x
0
=
11.5


x1≈11.4021739130435
x
1
≈
11.4021739130435


x2≈11.4017542587143
x
2
≈
11.4017542587143


x3≈11.4017542509914
x
3
≈
11.4017542509914


x4≈11.4017542509914
x
4
≈
11.4017542509914


Thus, with 15 digits of accuracy, we may state:

130−−−√≈11.4017542509914
130
≈
11.4017542509914


2.) Use the Babylonian method for your next estimate of square root 115 by using 10.7262 as your guess what's your next result?

The next result here is approximately:

x1=10.72622+1152⋅10.7262≈10.7238055620816
x
1
=
10.7262
2
+
115
2
⋅
10.7262
≈
10.7238055620816



3.) Nails wants to use the Babylonia method to estimate square root 58 to the nearest hundredth her initial estimate is 7.8. What is her estimate after she correctly completes the Babylonian method once?

The next result here is:

x1=7.82+582⋅7.8=7.6179487¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
x
1
=
7.8
2
+
58
2
⋅
7.8
=
7.6
179487
¯


4.) If you use the Babylonian method to estimate square root 75 to the nearest hundredth, starting with the estimate 8. What is the next estimate?

The next result here is:

x1=82+752⋅8=8.6875
x
1
=
8
2
+
75
2
⋅
8
=
8.6875
6 0
3 years ago
A geologist noticed that a land along a fault line moved 24.8 centimeters over the past 175 years in average how much did the la
Zigmanuir [339]

1.4171428571428571428571428571429 milimeters per year or,

0.14171428571428571428571428571429 centimeters per year.

8 0
3 years ago
Read 2 more answers
Which postulate or theorem, if any, could you use to show the two triangles are congruent?
frozen [14]

Answer:

ASA theorum

Step-by-step explanation:

we are given 1 side and 1 angle, other angle is vo of it corresponding equal angle

7 0
3 years ago
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