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Sholpan [36]
3 years ago
11

Theorem: The segment joining the midpoints of two sides of a triangle is parallel to the third side and half its length. A two-c

olumn proof of the theorem is shown, but the proof is incomplete. A triangle with vertices A is at 6, 8. B is at 2, 2. C is at 8, 4. Segment DE with point D on side AB and point E is on side BC Statement Reason The coordinates of point D are (4, 5) and coordinates of point E are (5, 3) Length of segment DE is Square root of 5 and length of segment AC is 2 multiplied by the square root of 5 By the distance formula Segment DE is half the length of segment AC By substitution Slope of segment DE is −2 and slope of segment AC is −2 By the slope formula Segment DE is parallel to segment AC Slopes of parallel lines are equal Which of the following completes the proof? (6 points) Select one: a. By the midpoint formula b. By definition of congruence c. Given d. By construction
Mathematics
2 answers:
Andre45 [30]3 years ago
8 0

Answer:

the thrid option im taking the test rn

Step-by-step explanation:

Lilit [14]3 years ago
3 0

Answer:

Midpoint Formula

Step-by-step explanation:

I just took the test sorry :(

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Help PLEASEEEE
Bumek [7]

Answer:

Segment AC = 10 units

segment AD =

angle 1 = 45°

angle 2 = 90°

AE = BE = CE = DE = 5

SEGMENT AC = AE + CE

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= 7 UNITS

ANGLE 1 = 90° ÷ 2

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2 years ago
How many times bigger is 3.45×10⁹ than 0.5×10⁴
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