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Sholpan [36]
3 years ago
11

Theorem: The segment joining the midpoints of two sides of a triangle is parallel to the third side and half its length. A two-c

olumn proof of the theorem is shown, but the proof is incomplete. A triangle with vertices A is at 6, 8. B is at 2, 2. C is at 8, 4. Segment DE with point D on side AB and point E is on side BC Statement Reason The coordinates of point D are (4, 5) and coordinates of point E are (5, 3) Length of segment DE is Square root of 5 and length of segment AC is 2 multiplied by the square root of 5 By the distance formula Segment DE is half the length of segment AC By substitution Slope of segment DE is −2 and slope of segment AC is −2 By the slope formula Segment DE is parallel to segment AC Slopes of parallel lines are equal Which of the following completes the proof? (6 points) Select one: a. By the midpoint formula b. By definition of congruence c. Given d. By construction
Mathematics
2 answers:
Andre45 [30]3 years ago
8 0

Answer:

the thrid option im taking the test rn

Step-by-step explanation:

Lilit [14]3 years ago
3 0

Answer:

Midpoint Formula

Step-by-step explanation:

I just took the test sorry :(

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Find the value of x.
bonufazy [111]

Answer:

61

Step-by-step explanation:

6 0
3 years ago
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How do you solve 2x^2 - 7x -5= 0 in quadratic form?
lesantik [10]

Answer:

Once the equation is in standard form, factor the quadratic expression. 2x2 + 7x + 3 = 0 (2x + 1)(x + 3) = 0. Using the Zero Product Property set ...

2x2 + 7x = -3

2x2 + 7x + 3 = 0

Once the equation is in standard form, factor the quadratic expression.

2x2 + 7x + 3 = 0

(2x + 1)(x + 3) = 0

Using the Zero Product Property set each factor equal to 0 and solve for x.

2x + 1 = 0  

2x + 1 - 1 = 0 - 1 x + 3 = 0

2x = -1 x + 3 - 3 = 0 - 3

2x 2 = -1 2 x = -3

x = -1 2  

The solutions to the equation are -1 2 and -3.

7 0
3 years ago
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What is the horizontal asymptote of f(x) = (2x+1)/ (x^2-4x+3) +2
evablogger [386]

Answer:

x=3 and x=1

Step-by-step explanation:Horizontal asymptote will occur at x=3 and x=1.

You have to factorize the denominator and find the zeroes of the denominator.  That is how you find out the horizontal asymoptote.

6 0
3 years ago
Hi, can you help to find (all the roots/zeros), please!!!
OLga [1]

Solution

Given the quadratic equation

x^2-2x-38=0

we need to find the zeros of the equation

To do that, we use the completing the square method

Step 1. Add 38 to both sides

\begin{gathered} \Rightarrow x^2-2x-38+38=38 \\  \\ \Rightarrow x^2-2x=38 \end{gathered}

Step 2: add the square of half of the coefficient of x to both sides

That is;

\begin{gathered} \Rightarrow x^2-2x+(\frac{1}{2}\cdot(-2))^2=38+(\frac{1}{2}\cdot(-2))^2 \\  \\ \Rightarrow x^2-2x+1=38+1 \\  \\ \Rightarrow x^2-2x+1=39 \\  \\ \Rightarrow(x-1)^2=39 \end{gathered}

Step 3: Simplify the above expression;

\begin{gathered} \Rightarrow x-1=\pm\sqrt[]{39} \\  \\ \Rightarrow x=1\pm\sqrt[]{39} \end{gathered}

4 0
1 year ago
What is 25 mi/h expressed as meters per second?
arlik [135]

Answer:

11.176 meters/second

Step-by-step explanation:

1 mile = 1609.34 meters

25 miles = 40233.6 meters

1 hour = 60 minutes

1 minute = 60 seconds

1 hour = 3600 seconds

40233.6 / 3600,

11.176 meters/second

7 0
1 year ago
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