Answer: See explanation
Step-by-step explanation:
John said he can find 38×10 by adding a 0 to the end of 38 to get 380. John finds 46.52×10 using the same method and gets 46.520.
For the first one that is, 38 × 10 = 380, John is correct. For the second one, that is, 46.52 × 10 = 46.520. John is incorrect. In this case, the first one is correct because John was multiplying by a whole number.
For the second one involving a decimal, John could have shifted the decimal point one place to the right and not add 0 to the end. Then he will get:
46.52 × 10 = 465.2
Answer:

Step-by-step explanation:
<u>Solving Equations Using Successive Approximations</u>
We need to find the solution to the equation

where


The approximation has been already started and reached a state for x=2.5 where


The difference between the results is 0.25, we need further steps to reach a good solution (to the nearest tenth)
Let's test for x=2.4


The new difference is -0.2+0.24=0.04
It's accurate enough, thus the solution is

Ok I think u have to do subtraction and in a negative way
Answer:
y = (-7/3)(x - 9)
Step-by-step explanation:
<em><u>(12, - 7)</u></em>
y = a(x - h)^2
-7 = a(12 - h)^2
- 7 = a(144 - 24x + h^2)
<em><u>(9,0)</u></em>
0 = a(x - h)^2
0 = a(9 - h)^2
0 = a(81 - 18h + h^2)
From (9,0) we can conclude that
a = 0
or
(9 - h)^2 = 0
Let's try the second possibility.
Take the square root of both sides.
9 - h = sqrt(0)
Add h to both sides
9 - h = 0
h = 9
So now what we have is
y = a(x - 9)
Use the first equation to get a
-7 = a(12 - 9)
-7 = a(3)
-7/3 = a
Answer
y = (-7/3)(x - 9)
16 n^2 -10n + 129 = 8n^2 -8
We collect the terms:
8n^2 -10n + 137 = 0
The steps for completing the square:
1) Move the "non X" (or "non N") term to the right:
8n^2 -10n = -137
<span>2)<span> Divide the equation by the coefficient of N² which in this case is 8
n^2 -1.2n = </span></span><span><span>-17.125
</span>
3) Take the coefficient of "N"; divide it by 2; square it; add it to both sides of the equation.
-1.2 / 2 = -.6
-.6^2 = .36
</span>
n^2 -1.2n +.36 = <span>-17.125
+.36
Take the square root of both sides:</span>
(n-.6)*(n-.6) = sq root(
<span>
<span>
<span>
-16.765
</span>
</span>
</span>
)
That's about as far as I can go.