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Vsevolod [243]
2 years ago
12

HELP NEED ANSWERS TO EDGEMS

Mathematics
1 answer:
Misha Larkins [42]2 years ago
6 0

1. (0, 1) , (2, -9) , (3, -14) , (-6, 31)

2. The amount she pays back each week.

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Andre45 [30]

Answer:

Solution,

Radius(r)=6 cm

Height(h)=20 cm

Volume of cylinder= pi (r)^2 h

=3.14*(6)^2*20

=3.14*36*20

=2260.8 cm^3

Hope it helps

Good luck on your assignment

4 0
3 years ago
Claire Drew model of 5/10 explain how Claire could change her model to show how many hundreds are in 5/10 I know this is like my
natta225 [31]

Answer:

There are 0.005 hundreds in 5/10.

Step-by-step explanation:

Claire drew model of 5/10

We want to know how many hundreds are in 5/10.

Let us use an obvious example.

There are three 2's in 6 right?

Suppose we didn't know this, and we are told to find how many 2's are in 6, we get this by representing this in an algebraic expression as:

There are x 2's in 6. This can be written as

2x = 6

Solving for x, by dividing both sides by 2, we have the number of 2's that are in 6.

x = 6/2 = 3.

Now, to our work

We want to find how many hundreds are in 5/10. We solve the equation

100x = 5/10

x = 5/1000 = 0.005

There are 0.005 hundreds in 5/10.

7 0
2 years ago
There are 22 rows of seats on a concert hall: 23 seats are in the 1st row, 27 seats on the 2nd row, 31 seats on the 3rd row, and
JulijaS [17]
We can model this situation with an arithmetic series.
we have to find the number of all the seats, so we need to sum up the number of seats in all of the 22 rows.

1st row: 23
2nd row: 27
3rd row: 31
Notice how we are adding 4 each time.

So we have an arithmetic series with a first term of 23 and a common difference of 4.

We need to find the total number of seats. To do this, we use the formula for the sum of an arithmetic series (first n terms):

Sₙ = (n/2)(t₁ + tₙ)

where n is the term numbers, t₁ is the first term, tₙ is the nth term

We want to sum up to 22 terms, so we need to find the 22nd term

Formula for general term of an arithmetic sequence:

tₙ = t₁ + (n-1)d,

where t1 is the first term, n is the term number, d is the common difference. Since first term is 23 and common difference is 4, the general term for this situation is

tₙ = 23 + (n-1)(4)

The 22nd term, which is the 22nd row, is

t₂₂ = 23 + (22-1)(4) = 107

There are 107 seats in the 22nd row.

So we use the sum formula to find the total number of seats:

S₂₂ = (22/2)(23 + 107) = 1430 seats

Total of 1430 seats.
If all the seats are taken, then the total sale profit is

1430 * $29.99 = $42885.70
4 0
3 years ago
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