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2 years ago

The app isn't letting me post the picture alone so this is just here so I can post the picture ;-;

Mathematics

1 answer:

labwork [276]2 years ago

7 0

Answer:

(x, y) = (0, -2248)

Step-by-step explanation:

Substitution

Substitute for y:

300x -2248 = 350x -2248

0 = 50x . . . . . . . . add 2248-300x to both sides

x = 0

y = 300·0 -2248

The solution is (x, y) = (0, -2248).

Elimination

Subtract the first equation from the second.

(y) -(y) = (350x -2248) -(300x -2248)

0 = 50x

x = 0

y = 300·0 -2248

The solution is (x, y) = (0, -2248).

Additional comment

If you think for a bit about what the graph looks like, you realize both lines cross at their y-intercept, (0, -2248). That point of intersection is the solution to the system of equations.

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In Exercises 45–48, let f(x) = (x - 2)2 + 1. Match the function with its graph

MA_775_DIABLO [31]

Answer:

45) The function corresponds to graph A

46) The function corresponds to graph C

47) The function corresponds to graph B

48) The function corresponds to graph D

Step-by-step explanation:

We know that the function f(x) is:

$f(x)=(x-2)^{2}+1$

45)

The function g(x) is given by:

$g(x)=f(x-1)$

using f(x) we can find f(x-1)

$g(x)=((x-1)-2)^{2}+1=(x-3)^{2}+1$

If we take the derivative and equal to zero we will find the minimum value of the parabolla (x,y) and then find the correct graph.

$g(x)'=2(x-3)$

$2(x-3)=0$

$x=3$

Puting it on g(x) we will get y value.

$y=g(3)=(3-3)^{2}+1$

$y=g(3)=1$

Then, the minimum point of this function is (3,1) and it corresponds to (A)

46)

Let's use the same method here.

$g(x)=f(x+2)$

$g(x)=((x+2)-2)^{2}+1$

$g(x)=(x)^{2}+1$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2x$

$0=2x$

$x=0$

Evaluatinf g(x) at this value of x we have:

$g(0)=(x)^{2}+1$

$g(0)=1$

Then, the minimum point of this function is (0,1) and it corresponds to (C)

47)

Let's use the same method here.

$g(x)=f(x)+2$

$g(x)=(x-2)^{2}+1+2$

$g(x)=(x-2)^{2}+3$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}+3$

$g(2)=3$

Then, the minimum point of this function is (2,3) and it corresponds to (B)

48)

Let's use the same method here.

$g(x)=f(x)-3$

$g(x)=(x-2)^{2}+1-3$

$g(x)=(x-2)^{2}-2$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}-2$

$g(2)=-2$

Then, the minimum point of this function is (2,-2) and it corresponds to (D)

I hope it helps you!

8 0

3 years ago

A farmer sold 3/5 of his oranges to a first customer and 90 oranges to a second customer. How many oranges did he have altogethe

enyata [817]

Answer:

He had 225 oranges to start with

6 0

3 years ago

Did y’all can’t couldn’t see the other one, here is this one, NEED HELP please and thank you

docker41 [41]

Answer:

god

Step-by-step explanation:

cause god is always the answer ;)

8 0

3 years ago

What are ALL the factors of 15

Sophie [7]

1&15 and 3&5 are factors of 15

3 0

3 years ago

How do you get the answer to 18,000 seconds = hrs?

Alex777 [14]

First you'd convert the seconds into minutes by dividing.

18,000 / 60 (60 secs in a min) = 300 minutes

Then, similarly, you would convert the minutes into hours.

300 / 60 (60 mins in an hr) = 5 hours

The answer is 5 hours.

5 0

3 years ago

Read 2 more answers

The app isn't letting me post the picture alone so this is just here so I can post the picture ;-;​

The app isn't letting me post the picture alone so this is just here so I can post the picture ;-;