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Montano1993 [528]
3 years ago
12

Convert each degree measure into radians

Mathematics
1 answer:
dimaraw [331]3 years ago
7 0

radians = degrees x PI/180

radians = 60 x pi/180 = 1.04719 radians

 round answer as needed


 if you need it in terms of pi it would be PI/3 radians

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The area of a circle is 28.26 square centimeters. What is its diameter (use 3.14 for ð)?
horsena [70]
Area for circle is  πr² so πr² =28.26 and we can sub 3.14 as pi
3.14*r²=28.26 we can divide by 3.14 to get r² on it's own
r²=28.26/3.14
then we root both sides to get r on it's own
28.26/3.14=9 √9=3
and the diameter is double the radius 3*2=6 so the diameter is 6

5 0
3 years ago
k is a an integer for which 1/2^1-k, 1/8. What is the value of k? 1/2^1-k must be equal to 1/8 if i read the question right.
svetlana [45]

Answer:

k = -2

Step-by-step explanation:

If \frac12^{1-k}=\frac18

Then

\frac1{2^{1-k}}=\frac18=\frac1{2^3}

So

1-k = 3

From this follows k = -2

3 0
4 years ago
Whats <br> 3(x+4) In simplyed.
Setler [38]

Answer:

3x + 12

Step-by-step explanation:

Distribute the 3

5 0
3 years ago
Read 2 more answers
A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex
Olenka [21]

Answer:

a

 The  90% confidence interval that  estimate the true proportion of students who receive financial aid is

     0.533  <  p <  0.64

b

   n = 1789

Step-by-step explanation:

Considering question a

From the question we are told that

      The sample size is  n = 200

      The number of student that receives financial aid is k = 118

Generally the sample proportion is  

      \^ p = \frac{k}{n}

=>   \^ p = \frac{118}{200}

=>   \^ p = 0.59

From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90 ) \%

=>   \alpha = 0.10

Generally from the normal distribution table the critical value  of \frac{\alpha }{2}  is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

 =>E =  1.645 * \sqrt{\frac{0.59 (1- 0.59)}{200} }

=>  E = 0.057

Generally 90% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

  =>  0.533  <  p <  0.64  

Considering question b

From the question we are told that

    The margin of error  is  E = 0.03

From the question we are told the confidence level is  99% , hence the level of significance is    

      \alpha = (100 - 99 ) \%

=>   \alpha = 0.01

Generally from the normal distribution table the critical value  of   is  

   Z_{\frac{\alpha }{2} } = 2.58

Generally the sample size is mathematically represented as      

        [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=>      n = [\frac{2.58}{0.03} ]^2 * 0.59 (1 - 0.59 )

=>      n = 1789

8 0
3 years ago
Help?????????????????
lesantik [10]
Y = -4x
**************************************************************************

8 0
3 years ago
Read 2 more answers
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