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3 years ago

Please help me (6+6)/2=

Mathematics

2 answers:

natulia [17]3 years ago

6 0

Answer:

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Step-by-step explanation:

Step 1: Define

(6 + 6)/2

Step 2: Evaluate

(Parenthesis) Add: 12/2
Divide: 6

Serggg [28]3 years ago

4 0

(6+6)/2= 6 SO THE ANSWER IS 6

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Can anyone help me with this?

Maurinko [17]

Answer:

D. -6m²n² + 10m²n + 8mn² - 10mn

Step-by-step explanation:

(-7mn + 8mn² - 8m²n²) + (10m²n + 2m²n² - 3mn)

Apply the distributive property to remove the parentheses

-7mn + 8mn² - 8m²n² + 10m²n + 2m²n² - 3mn

Combine like terms together and arrange in standard form

-7mn + 8mn² - 8m²n² + 10m²n + 2m²n² - 3mn

-8m²n² + 2m²n² + 10m²n + 8mn² - 7mn - 3mn

-6m²n² + 10m²n + 8mn² - 10mn

5 0

3 years ago

Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago

The product-3 and t is greater than 11

PSYCHO15rus [73]

Answer:

i am pretty sure its 8

Step-by-step explanation:

because a negative plus a positive = wichever one is bighger and 8 is bigger than 3 so 11 is positive. 8 +3 = 11

6 0

3 years ago

Complete the equation: x^2+8x + _=(_)^2

pentagon [3]

Answer:

x^2+8x+16=(x-4)^2

EXPLANATION:

(a+b)^2=a2+2.a.b+b2

we have to break the middle term in 2ab here a is x then 2xb=8x, => b=4, but value of a and b to get the required equation!

8 0

3 years ago

Lines m and n are parallel. Which angle has a measure of 110°?

grigory [225]

This might help you..need more information

6 0

2 years ago