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Lilit [14]
3 years ago
12

How do I do this. I don’t understand how to move place values

Mathematics
1 answer:
Drupady [299]3 years ago
5 0

For this case we must indicate the value of the following expression, expressed in scientific notation:

(1.2 * 10^{-3}) * (1.1 * 10^{8}) =

We have that for multiplication properties of powers of the same base, the same base is placed and the exponents are added:

a ^ n * a ^ m = a ^ {n + m}

Then, rewriting the expression we have:

(1.2 * 1.1) * 10 ^{- 3 + 8} =\\1.32 * 10 ^ 5

Answer:

1.32 * 10 ^ 5

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Please Complete the page.
Alexxandr [17]
7. -8/3
8. 4/35
9. -21/50
10. 35/64
11.-25/54
6 0
3 years ago
I need help with this please!! ​
vovangra [49]

Answer:

{6x}^{3}  +  {9x}^{2}  - 18x + 3

Step-by-step explanation:

1. Expand by distributing sum groups.3x( {2x}^{2}  + 5x - 1) - 3( {2x}^{2}  + 5x - 1)

2. Expand by distributing terms.

{6x}^{3}  +  {15x}^{2}  - 3x - 3( {2x}^{2}  + 5x - 1)

3.Expand by distributing terms.

{6x}^{3}  +  {15x}^{2}  - 3x - ( {6x}^{2}  +  15x - 3)

4. Remove parentheses.

{6x}^{3}  +  {15x}^{2}  - 3x -  {6x}^{2}  - 15x + 3

5. Collect like terms.

{6x}^{3}  +  {15x}^{2}  -  {6x}^{2} ) + ( - 3x - 15x) + 3

6. Simplify.

{6x}^{3}  +  {9x}^{2}  - 18x + 3

Thus. the answer is,

{6x}^{3}  +  {9x}^{2}  - 18x + 3

5 0
2 years ago
Rotate ΔABC with vertices A(-1, 4), B(2, 1), and C(3, -3) about the origin by 90°.
MAXImum [283]
You got this you can do it I don’t know the answer but I hope you find someone who does(:
4 0
3 years ago
What's 9 + 10? What's 1 + 1? What's 2 + 2? What's 9 * 9? What's 12 * 12? What's 8999000 * 4499000​
Vlad1618 [11]

Answer:9+10 is 19

1+1 is 2

2+2=4

9 * 9 is 81

12 * 12= 144

last one not sure

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Remember to show work and explain. Use the math font.
MrMuchimi

Answer:

\large\boxed{1.\ f^{-1}(x)=4\log(x\sqrt[4]2)}\\\\\boxed{2.\ f^{-1}(x)=\log(x^5+5)}\\\\\boxed{3.\ f^{-1}(x)=\sqrt{4^{x-1}}}

Step-by-step explanation:

\log_ab=c\iff a^c=b\\\\n\log_ab=\log_ab^n\\\\a^{\log_ab}=b\\\\\log_aa^n=n\\\\\log_{10}a=\log a\\=============================

1.\\y=\left(\dfrac{5^x}{2}\right)^\frac{1}{4}\\\\\text{Exchange x and y. Solve for y:}\\\\\left(\dfrac{5^y}{2}\right)^\frac{1}{4}=x\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\dfrac{(5^y)^\frac{1}{4}}{2^\frac{1}{4}}=x\qquad\text{multiply both sides by }\ 2^\frac{1}{4}\\\\\left(5^y\right)^\frac{1}{4}=2^\frac{1}{4}x\qquad\text{use}\ (a^n)^m=a^{nm}\\\\5^{\frac{1}{4}y}=2^\frac{1}{4}x\qquad\log_5\ \text{of both sides}

\log_55^{\frac{1}{4}y}=\log_5\left(2^\frac{1}{4}x\right)\qquad\text{use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\\dfrac{1}{4}y=\log(x\sqrt[4]2)\qquad\text{multiply both sides by 4}\\\\y=4\log(x\sqrt[4]2)

--------------------------\\2.\\y=(10^x-5)^\frac{1}{5}\\\\\text{Exchange x and y. Solve for y:}\\\\(10^y-5)^\frac{1}{5}=x\qquad\text{5 power of both sides}\\\\\bigg[(10^y-5)^\frac{1}{5}\bigg]^5=x^5\qquad\text{use}\ (a^n)^m=a^{nm}\\\\(10^y-5)^{\frac{1}{5}\cdot5}=x^5\\\\10^y-5=x^5\qquad\text{add 5 to both sides}\\\\10^y=x^5+5\qquad\log\ \text{of both sides}\\\\\log10^y=\log(x^5+5)\Rightarrow y=\log(x^5+5)

--------------------------\\3.\\y=\log_4(4x^2)\\\\\text{Exchange x and y. Solve for y:}\\\\\log_4(4y^2)=x\Rightarrow4^{\log_4(4y^2)}=4^x\\\\4y^2=4^x\qquad\text{divide both sides by 4}\\\\y^2=\dfrac{4^x}{4}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\y^2=4^{x-1}\Rightarrow y=\sqrt{4^{x-1}}

6 0
3 years ago
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