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3 years ago

Help if your smart plzzzzzzz ( will give 35 pts and brainliest)

Mathematics

1 answer:

Temka [501]3 years ago

4 0

Answer:

a) alternate interior angles theorem

b) OXP ≅ XOL

c) XO ≅ OX

d) reflexive property (i'm not sure about this one)

e) ΔXOP ≅ ΔOXL

f) cpctc

make sure to double check the fourth one

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NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!! THIS IS NOT A TEST OR AN ASSESSMENT!! Please help me with these math questions

Art [367]

Answer:

See below

Step-by-step explanation:

3. What are two ways that a vector can be represented?

Considering a vector $\vec{v}$ in some vector space $\mathbb R^n$ we have

$\vec{v} = \langle a,b\rangle$

This is the component form. I don't like that way. It is probably used in high school, but

$\vec{v} = \begin{pmatrix} a\\ b\\ \end{pmatrix}$

is preferable because the inner product on $\mathbb R^n$ is defined to be

$\langle a,b\rangle := \sum_{i = 1}^n a_i b_i$

You can also write it using linear form such as $\vec{v} = 2i+2j$

For this question, I think you meant

vectors

$\vec{u_1} = (-8, 12)$

$\vec{u_2} = (13, 15)$

Once

$\cos(\theta)=\dfrac{\vec{u_1} \cdot\vec{u_2}}{||\vec{u_1}||||\vec{u_2}||}$

Considering that the dot product is

$\vec{u_1}\cdot \vec{u_2} = (-8)\cdot 13 + 12\cdot 15 = -104+180= 76$

and the norm of $\vec{u_1}$ is $||\vec{u_1}|| = \sqrt{(-8)^2 + 12^2} = \sqrt{64 + 144}= \sqrt{208}$

and the norm of $\vec{u_2}$ is $||\vec{u_2}|| = \sqrt{13^2 + 15^2} = \sqrt{169 + 225}= \sqrt{394}$

Thus,

$\cos(\theta)=\dfrac{76}{\sqrt{208} \sqrt{394}} = \dfrac{19}{\sqrt{13}\sqrt{394}}=\dfrac{19}{\sqrt{5122}}$

$\therefore \theta = \arccos \left(\dfrac{19}{\sqrt{5122}} \right)$

3 0

3 years ago

Show steps <br> Simplify <img src="https://tex.z-dn.net/?f=%5Csqrt%7B81%7D" id="TexFormula1" title="\sqrt{81}" alt="\sqrt{81}" a

AysviL [449]

The square root of 81 is 9

4 0

3 years ago

Read 2 more answers

HELP ME ASAP, DUE TODAY!!!!!!<br> WILL MARK BRAINIEST

lana [24]

Answer:

Q' = ( 1, 3 )

R' = ( 3, -3)

S' = ( 0, -2)

T' = ( -2, 1 )

4 0

3 years ago

How many real-number solutions does the equation have?

Nataly_w [17]

Answer:

Option b. Two solutions

Step-by-step explanation:

In order to find how many real number solutions the equation has we have to solve it

Given equation: -4x² + 10x + 6 = 0

taking 2 common from the equation

2(-2x² + 5x + 3) = 0

-2x² + 5x + 3 = 0

taking minus sign common from the above equation

2x² - 5x - 3 = 0

We will solve this equation by factorization in such a way that the sum of two factors is equal to -5x and the product is -6x²

2x² - 6x + x - 3 = 0

taking common above

2x(x-3) + 1(x-3) = 0

taking (x-3) common

(2x+1)(x-3) = 0

2x + 1 = 0

2x = -1

x = $\frac{-1}{2}$

x - 3 = 0; x = 3

the solutions are

$x=\frac{-1}{2},3$

Both values are real numbers, therefore correct option is b

7 0

3 years ago

Read 2 more answers

Write the equation in standard form for the circle with center (0, -1) and radius 10.

BARSIC [14]

Answer:

x^2 + (y+1)^2 = 10^2

Step-by-step explanation:

Centre (p,q) = (0, -1)

radius, r = 10

General Equation of a circle

(x-p)^2 + (y-q)^2 = r^2

(x-0)^2 + (y- -1)^2 = 10^2

x^2 + (y+1)^2 = 10^2

7 0

3 years ago