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2 years ago

8

A counter recorded 254 revolutions of the bicycle wheel shown below how far did the bicycle travel. Use 22/7 as pi and the diame

ter of the wheel is 5/4.''
''a) how far does the wheel roll for one tire revolution''
''b) what is the total distance recorded''
Show your work

2 answers:

pickupchik [31]2 years ago

6 0

Answer:

Step-by-step explanation:

hichkok12 [17]2 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

A train leaves Boston at 10:20 AM and arrives in Stamford at 1:00 PM. Find the distance between the stations if the average spee

mina [271]

60 mph = 1 mile per minute
10:20 AM -> 1:00 PM = 2 hours and 40 minutes
2 hours 40 minutes = 160 minutes
Boston -> Stamford = 160 miles

4 0

3 years ago

What is pi times 3?<br> Thank you!!!

natta225 [31]

The correct answer is 9.42477796077 because pi 3.14ect you would just multiply it by 3 so the answer would be 9.42477796077

4 0

3 years ago

Pls show full working out

sweet-ann [11.9K]

Answer:

Question 1a. i) $x=1.8m$

Question 1a. ii) $Volume=27.6m^3$

Question 1b) $Volume=65.9m^3$

Explanation:

<u><em>Question 1 a. i) Find the value of x.</em></u>

$tan(\theta )=\dfrac{opposite\text{ }leg}{adjacent\text{ }leg}$

For the smalll triangle you can write:

$tan(\theta )=\dfrac{x}{1m}$

For tthe big triangle:

$tan(\theta )=\dfrac{x+2.7m}{2.5m}$

Substitute:

$\dfrac{x}{1m}=\dfrac{x+2.7m}{2.5m}$

Solve for x:

$2.5x=x+2.7m\\\\2.5x-x=2.7m\\\\1.5x=2.7m\\\\x=2.7m/1.5\\\\x=1.8m$

<u><em>Question 1a ii) Find the volume of the frustrum</em></u>

Find the volume of a cone with height = 2.7m + 1.8m = 4.5m, and radius = 2.5m

Formula:

$Volume=(1/3)\pi \times radius^2\times height$

Substitute:

$Volume=(1/3)\pi \times (2.5m)^2\times 4.5m=9.375\pi m^3$

Find the volume of a cone with heigth = 1.8m and radius = 1m

$Volume=(1/3)\pi \times (1m)^2\times 1.8m=0.6\pi m^3$

Subtract the volume of the small cone from the volume of the big cone

$Volume\text{ }of\text{ }frustrum=9.375\pi m^3-0.6\pi m^3=8.775\pi m^3\approx 27.6m^3$

<u><em>Question 1b. Calculate the volume of the bin</em></u>

<u>i) Upper frustrum</u>

This is the same frustrum from the equation of above, thus ist volume is 27.6m³.

<u>ii) Lower frustrum</u>

$\dfrac{x}{2.0m}=\dfrac{x+2.4m}{2.5m}$

$2.5x=2(x+2.4m)\\\\2.5x=2x+4.8m\\\\0.5x=4.8m\\\\x=9.6m$

$Volume=(1/3)\pi \times (2.5m)^2\times (9.6m+2.4m)-(2.0m)^2\times (9.6m)$

$Volume=38.3m^3$

<u>iii) Add the volume of the two frustrums</u>

$Volume=27.6m^3+38.3m^3=65.9m^3$

6 0

3 years ago

Major help and if you can, please explain how you got your answer

hjlf

The correct answer is: [A]: " 384 in² " .
_______________________________________________________

Explanation:
______________________________________________________
The formula for the surface area of a cube is:
______________________________________________________

→ A = 6a² ;
______________________________________________________ → in which:
______________________________________________________
  A = surface area of the cube— for which we shall solve ;
(in "square units" ; or, " in² " ; in our case) ;

a = side length = " 8 in " (given);

→ Note: A cube has all equal side lengths.

→ The "6" in the formula accounts for "6 sides" of a cube.

_______________________________________________________

→ To solve for the surface area of the cube; plug in our known value(s);
& solve; as follows:
_______________________________________________________
  → A = 6 a² ;

= 6 * (8 in)² ;

= 6 * 8² * in² ;

= 6 * 8 * 8 * in² ;

= 48 * 8 * in² ;

= 384 in² ;
_______________________________________________________
The answer is: " 384 in² " ;

→ which is: Answer choice: [A]: " 384 in² " .
_______________________________________________________

8 0

3 years ago

I have tried so hard and I cant figure thus out. The. entire problem needs to be finished, this is worth 20 points.

bija089 [108]

Answer:

No the ramp doesn’t meet the law. The slope is 4/50 which is 1/12.5

The slope of the ramp doesn’t meet the law because it’s slope is greater than 1/12. To adjust the ramp so that it meets the law, you could increase the height and/or the horizontal length to increase the slope so it is less than 1/12.

Step-by-step explanation:

5 0

3 years ago