In a npn transistor the current ie that flows in the emitter circuit is
1 answer:
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Answer:
zero
Explanation:
q = 6.4 nC = 6.4 x 1 0^-9 C
d = 16 cm = 0.16 m
r = 16 / 2 = 8 cm = 0.08 m
Electric field at P due to the charge placed at A
Ea = k q / r^2
Ea = ( 9 x 10^9 x 6.4 x 10^-9) / (0.08 x 0.08) Towards right
Ea = 9000 Towards right
Electric field at P due to the charge placed at B
Eb = k q / r^2
Eb = ( 9 x 10^9 x 6.4 x 10^-9) / (0.08 x 0.08) Towards left
Eb = 9000 Towards left
The magnitude of electric field is same but teh direction is opposite, so the resultant electric field at P is zero.
Answer:
critical angle is the angle of incidence in optically denser medium, for which the angle of reflection in the less denser medium is 90 degree
Explanation:
total internal reflection occurs at one particular angle of incidence where the reflected ray lies on the boundary.
this angle is called the critical angle
We have that the Velocities is mathematically given as
a)v=2.8e5m/s
b)v_2=3.11e5m/s
From the question we are told
- Consider the parallel-plate <u>capacitor </u>shown in the figure.
- The plate separation is 1.8 mm and the the electric field inside is 23 N/C.
- An electron is positioned halfway between the plates and is given some initial velocity, vi.
Generally the equation for the workdone is mathematically given as
a)
v=2.8e5m/s
b)
applying work
v_2=3.11e5m/s
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