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fiasKO [112]
3 years ago
5

How do I solve for x

Mathematics
1 answer:
Bond [772]3 years ago
8 0

Answer:

you have to figure out how big the angle is and then add the 38 and 21 and subtract that from the total i dont know if any of that made sense

Step-by-step explanation:

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Is anyone good with geometry? If yes, please show your work on these questions so i can see how its done. C:
Dvinal [7]

(7)

if r perpendicular to s then angles 1,2,3,4=90 deg.

if t perpendicular to s then angles 5,6,7,8=90 deg.

If two different lines intersect a third line at the same angle then they must be parallel.

r and t intersect s at the angle 2=90 deg  and 6 = 90 deg, therefore r and t are parallel.

(6) use sum of angles in a triange =180 deg property.

first, the complement to 105 is an angle of 75 deg. then x=180-(24+75)=81 deg

x=81 deg

(5)

\angle STU=180-\angle STR=180- \angle SRT   \\\\\4x = 180-20=160\\\\x=40

(4) sum of angles = 180 deg

62 +45 + k = 180

k = 180 -107  = 73

k = 73


6 0
4 years ago
QUICK PLS Your friend is able to invest $120 a month in a 401(k) with a predicted growth rate of 3%. Your friend's company will
Len [333]
  • The contribution of the friend's company is of: $60.
  • The account's balance after 20 years will be of: $130,694.36.
  • The total deposits after 20 years are given as follows: $28,800 by the friend and $14,400 by the company.
  • The interest earned during this entire period was of: $87,494.36.

<h3>How to obtain the balance?</h3>

The balance is obtained using the future value formula, which is presented as follows:

B = \frac{P\left(\left(1 + \frac{r}{n}\right)^{nt}-1\right)}{\frac{r}{n}}

The meaning of each parameter is explained as follows:

  • P is the total month deposit.
  • r is the interest rate.
  • n is the number of coupoundings per period, that is, compoundings per year.
  • t is the number of years.

The deposits will be of:

  • Friend: $120.
  • Company: $60, as it is half of the friend.

Then the parameter P is of:

P = 120 + 60 = 180.

The remaining parameters to obtain the balance after 20 years are given as follows:

r = 0.03, n = 12, t = 20.

Then the balance after 20 years is obtained as follows:

B = \frac{P\left(\left(1 + \frac{r}{n}\right)^{nt}-1\right)}{\frac{r}{n}}

B = \frac{180\left(\left(1 + \frac{0.03}{12}\right)^{12 \times 20}-1\right)}{\frac{0.03}{12}}

B = $130,694.36.

The total deposits will be of:

  • Friend: 120 x 20 x 12 = $28,800.
  • Company: half of friend -> $14,400.

The interest accrued is the balance subtracted by the total deposits, hence:

130694.36 - (28800 + 14400) = $87,494.36.

A similar problem, also featuring the future value formula, is presented at brainly.com/question/24703884

#SPJ1

3 0
1 year ago
The number of electrical outages in a city varies from day to day. Assume that the number of electrical outages ( x ) in the cit
forsale [732]

Answer:

Therefore, the mean and the standard deviation for the number of electrical outages (respectively) are 0.26 and 0.5765 respectively.

Step-by-step explanation:

Given the probability distribution table below:

\left|\begin{array}{c|cccc}x&0&1&2&3\\P(x)&0.8&0.15&0.04&0.01\end{array}\right|

(a)Mean

Expected Value, \mu =\sum x_iP(x_i)

=(0*0.8)+(1*0.15)+(2*0.04)+(3*0.01)

=0+0.15+0.08+0.03

Mean=0.26

(b)Standard Deviation

(x-\mu)^2\\(0-0.26)^2=0.0676\\(1-0.26)^2=0.5476\\(2-0.26)^2=3.0276\\(3-0.26)^2=7.5076

Standard Deviation =\sqrt{\sum (x-\mu)^2P(x)}

=\sqrt{0.0676*0.8+0.5476*0.15+3.0276*0.04+7.5076*0.01}\\=\sqrt{0.3324}\\=0.5765

Therefore, the mean and the standard deviation for the number of electrical outages (respectively) are 0.26 and 0.5765 respectively.

3 0
3 years ago
What are the values of a, b, and c in the matrix addition below?
patriot [66]

a =  - 14 \\ c =  - 12 \\ b =  - 9

3 0
3 years ago
Which value is a solution of the equation 2-8x=-6 ?
lyudmila [28]
A. 1

2 - 8(1) = -6
-6 = -6
8 0
3 years ago
Read 2 more answers
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