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ololo11 [35]
3 years ago
13

HELP ME SOMEBODY PLEASE 8 more

Mathematics
2 answers:
Sedaia [141]3 years ago
7 0

Answer:

D

Step-by-step explanation:

The correct answer is D because it is the lowest number. If you did the largest number it is more likely to happen.

Snezhnost [94]3 years ago
4 0

Answer:C

Step-by-step explanation:

I think

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Step 1 Find the least common denominator
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4 years ago
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X and y are normal random variables with e(x) = 2, v(x) = 5, e(y) = 6, v(y) = 8 and cov(x,y)=2. determine the following: e(3x 2y
andriy [413]

The result for the given normal random variables are as follows;

a. E(3X + 2Y) = 18

b. V(3X + 2Y) = 77

c. P(3X + 2Y < 18) = 0.5

d. P(3X + 2Y < 28) = 0.8729

<h3>What is normal random variables?</h3>

Any normally distributed random variable having mean = 0 and standard deviation = 1 is referred to as a standard normal random variable. The letter Z will always be used to represent it.

Now, according to the question;

The given normal random variables are;

E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8.

Part a.

Consider E(3X + 2Y)

\begin{aligned}E(3 X+2 Y) &=3 E(X)+2 E(Y) \\&=(3) (2)+(2)(6 )\\&=18\end{aligned}

Part b.

Consider V(3X + 2Y)

\begin{aligned}V(3 X+2 Y) &=3^{2} V(X)+2^{2} V(Y) \\&=(9)(5)+(4)(8) \\&=77\end{aligned}

Part c.

Consider P(3X + 2Y < 18)

A normal random variable is also linear combination of two independent normal random variables.

3 X+2 Y \sim N(18,77)

Thus,

P(3 X+2 Y < 18)=0.5

Part d.

Consider P(3X + 2Y < 28)

Z=\frac{(3 X+2 Y-18)}{\sqrt{77}}

\begin{aligned} P(3X + 2Y < 28)&=P\left(\frac{3 X+2 Y-18}{\sqrt{77}} < \frac{28-18}{\sqrt{77}}\right) \\&=P(Z < 1.14) \\&=0.8729\end{aligned}

Therefore, the values for the given normal random variables are found.

To know more about the normal random variables, here

brainly.com/question/23836881

#SPJ4

The correct question is-

X and Y are independent, normal random variables with E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8. Determine the following:

a. E(3X + 2Y)

b. V(3X + 2Y)

c. P(3X + 2Y < 18)

d. P(3X + 2Y < 28)

8 0
2 years ago
HELP ME PLEASE I NEEED A GOOD GRADE DESPERATELY!!!!!
liubo4ka [24]

Answer:

1.

Step-by-step explanation:

5 0
3 years ago
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3 years ago
The slant asymptote of f(x)=x^2-4x+1/2x-3 is y=1/2x-5/4 <br> t or f
sveta [45]

Answer:

True

Step-by-step explanation:

Given that a function is

f(x)=\frac{x^2-4x+1}{2x-3}

We are to find the slant asymptote if any for this function

Since numerator is of degree 2 and denominator 1, let us divide and then check

Doing long division we find

f(x)=\frac{1}{2} [x-\frac{5}{2} ]-\frac{11}{4(2x-3)}

Thus we find the asymptote y= the quotient obtained i.e

\frac{1}{2} [x-\frac{5}{2} ]\\=\frac{x}{2} -\frac{5}{4}

Hence asymptote is

y=1/2x-5/4

Statement given is true.

4 0
3 years ago
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