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docker41 [41]
3 years ago
12

10q – 25q*2 Use the distributive property

Mathematics
1 answer:
marissa [1.9K]3 years ago
7 0

Answer:

2q-5q*2 OR 8q

Step-by-step explanation:

(im very confused by the way you formatted the question so forgive me if i'm wrong or don't give the solution you want)

10q-25q*2 -- given

2q-5q*2-- distributive property, factored out 5q, since it is 5q the 2 is unaffected that is why this is possible.

2q-10q-- simplify

8q-- simplify

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At an airport, it cost 7 to park for one hour and 5 per hour for each additional hour.Let x represent the number hours parked.wr
kompoz [17]
The cost of parking is an initial cost plus an hourly cost.
The first hour costs $7.
You need a function for the cost of more than 1 hour,
meaning 2, 3, 4, etc. hours.
Each hour after the first hour costs $5.

1 hour: $7
2 hours: $7 + $5                  = 7 + 5 * 1          = 12
3 hours: $7 + $5 + $5          = 7 + 5 * 2          = 17
4 hours: $7 + $5 + $5 + $5  = 7 + 5 * 3          = 22

Notice the pattern above in the middle column.
The number of $5 charges you add is one less than the number of hours.
For 2 hours, you only add one $5 charge.
For 3 hours, you add two $5 charges.

Since the number of hours is x, according to the problem, 1 hour less than the number of hours is x - 1.

The fixed charge is the $7 for the first hour.
Each additional hour is $5, so you multiply 1 less than the number of hours,
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C(x) = 7 + 5(x - 1)

This can be left as it is, or it can be simplified as

C(x) = 7 + 5x - 5

C(x) = 5x + 2

Answer: C(x) = 5x + 2

Check:
For 2 hours: C(2) = 5(2) + 2 = 10 + 2 = 12
For 3 hours: C(3) = 5(3) + 2 = 15 + 2 = 17
For 4 hours: C(3) = 5(4) + 2 = 20 + 2 = 22
Notice that the totals for 2, 3, 4 hours here
are the same as the right column in the table above.
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4 years ago
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erastova [34]
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Step-by-step explanation:

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Troyanec [42]

Answer:

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Step-by-step explanation:

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The number of possible combinations

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Step-by-step explanation:

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