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2 years ago

15

At a pet store, Davina counted 12 parrots out of 20 birds. Which is an equivalent ratio of parrots to birds at the pet store? A.

2:3 B.3 to 2 C5 3 D3 to 5 Markuthandel Save and Exit Next Subt answer fast plz ty

2 answers:

Rina8888 [55]2 years ago

7 0

The answer is d because the reduced fraction of 12/20 is 3/5

Andreas93 [3]2 years ago

6 0

Which group of organisms would Schleiden have been most likely to study?

flower, pine tree, or cactus
mushroom, slime mold, or mildew
jellyfish, elephant, or jaguar
ant, spider, or beetle

You might be interested in

Been posting this question for days now (Q5) ....pls I beg of you if you don't know don't reply

Firdavs [7]

Answer:

a. Another letter that have corresponding angles is the letter 'E'

b. Another letter that have alternate angles is the letter 'N'

Step-by-step explanation:

The capital letter 'F' can be described as letter can be presented as follows;

Two horizontal parallel lines touching and perpendicular to a common transversal

Therefore, the parallel lines in the letter 'F' and their common transversal form corresponding angles below each parallel line and the common transversal

The two horizontal lines in the capital letter Z and the inclined transversal form alternate angles between the transversal and the parallel lines, in the region between the parallel lines and on opposite sides of the transversal

a. Another letter that have corresponding angles is the letter 'E'

b. Another letter that have alternate angles is the letter 'N'

5 0

3 years ago

Mrs. Bautista invested Php2700.00 part at 8% and the rest at 11% .How musch did she invest at each rate if her total annual inco

Margarita [4]

Answer:

The answer to the question is

She invested

Php2700.00 at 8 % and

Php 20,400.00 at 11 %

Step-by-step explanation:

To solve the question we note that

Simple interest is given by $\frac{P*R*T}{100}$ where

P= Principal, R = Rate and T = Time

If we call the first part P₁, T₁, and R₁ and the second part

P₂, T₂, and R₂

Then ${P_1*(1+R_1*T_1}) +{P_*(1+R_2*T_2}) = 2460.00$

= 2700×0.08×1 + P₂×0.11×1 = 2460 which gives

2244÷0.11 = P₂ or P₂ = Php 20,400.00

That is she invested

Php2700.00 at 8 % and

Php 20,400.00 at 11 %

5 0

2 years ago

Two major automobile manufacturers have produced compact cars with engines of the same size. We are interested in determining wh

Molodets [167]

Answer:

(A) The mean for the differences is 2.0.

(B) The test statistic is 1.617.

(C) At 90% confidence the null hypothesis should not be rejected.

Step-by-step explanation:

We are given that a random sample of eight cars from each manufacturer is selected, and eight drivers are selected to drive each automobile for a specified distance.

The following data (in miles per gallon) show the results of the test;

Driver Manufacturer A Manufacturer B

1 32 28

2 27 22

3 26 27

4 26 24

5 25 24

6 29 25

7 31 28

8 25 27

Let $\mu_1$ = mean MPG for the fuel efficiency of Manufacturer A brand

$\mu_2$ = mean MPG for the fuel efficiency of Manufacturer B brand

SO, Null Hypothesis, $H_0$ : $\mu_1-\mu_2=0$ or $\mu_1= \mu_2$ {means that there is a not any significant difference in the mean MPG (miles per gallon) when testing for the fuel efficiency of these two brands of automobiles}

Alternate Hypothesis, $H_A$ : $\mu_1-\mu_2\neq 0$ or $\mu_1\neq \mu_2$ {means that there is a significant difference in the mean MPG (miles per gallon) for the fuel efficiency of these two brands of automobiles}

The test statistics that will be used here is <u>Two-sample t test statistics</u> as we don't know about the population standard deviations;

T.S. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t__n__1+_n__2-2$

where, $\bar X_1$ = sample mean MPG for manufacturer A = $\frac{\sum X_A}{n_A}$ = 27.625

$\bar X_2$ = sample mean MPG for manufacturer B = $\frac{\sum X_B}{n_B}$ = 25.625

$s_1$ = sample standard deviation for manufacturer A = $\sqrt{\frac{\sum (X_A-\bar X_A)^{2} }{n_A-1} }$ = 2.72

$s_2$ = sample standard deviation manufacturer B = $\sqrt{\frac{\sum (X_B-\bar X_B)^{2} }{n_B-1} }$ = 2.20

$n_1$ = sample of cars selected from manufacturer A = 8

$n_2$ = sample of cars selected from manufacturer B = 8

Also, $s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(8-1)\times 2.72^{2}+(8-1)\times 2.20^{2} }{8+8-2} }$ = 2.474

(A) The mean for the differences is = 27.625 - 25.625 = 2

(B) <u><em>The test statistics</em></u> = $\frac{(27.625-25.625)-(0)}{2.474 \times \sqrt{\frac{1}{8}+\frac{1}{8} } }$ ~ $t_1_4$

= 1.617

(C) Now at 10% significance level, the t table gives critical values between -1.761 and 1.761 at 14 degree of freedom for two-tailed test. Since our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that there is a not any significant difference in the mean MPG (miles per gallon) when testing for the fuel efficiency of these two brands of automobiles.

5 0

3 years ago

Will I ever get an answer?

JulsSmile [24]

(5/8) / (3/8) =
5/8 * 8/3 =
5/3 =
1 2/3....a = 1, b = 2, c = 3

5 0

2 years ago

The Wall Street Journal reported that Walmart Stores Inc. is planning to lay off 2300 employees at its Sam's Club warehouse unit

Advocard [28]

Answer:

(a) The mean is 52 and the median is 55.

(b) The first quartile is 44 and the third quartile is 60.

(c) The value of range is 33 and the inter-quartile range is 16.

(d) The variance is 100.143 and the standard deviation is 10.01.

(e) There are no outliers in the data set.

(f) Yes

Step-by-step explanation:

The data provided is:

S = {55, 56, 44, 43, 44, 56, 60, 62, 57, 45, 36, 38, 50, 69, 65}

(a)

Compute the mean of the data as follows:

$\bar x=\frac{1}{n}\sum x\\=\frac{1}{15}[55+ 56+ 44+ 43+ 44+ 56+ 60+ 62+ 57+ 45 +36 +38 +50 +69+ 65]\\=\frac{780}{15}\\=52$

Thus, the mean is 52.

The median for odd set of values is the computed using the formula:

$Median=(\frac{n+1}{2})^{th}\ obs.$

Arrange the data set in ascending order as follows:

36, 38, 43, 44, 44, 45, 50, 55, 56, 56, 57, 60, 62, 65, 69

There are 15 values in the set.

Compute the median value as follows:

$Median=(\frac{15+1}{2})^{th}\ obs.=(\frac{16}{2})^{th}\ obs.=8^{th}\ observation$

The 8th observation is, 55.

Thus, the median is 55.

(b)

The first quartile is the middle value of the upper-half of the data set.

The upper-half of the data set is:

36, 38, 43, 44, 44, 45, 50

The middle value of the data set is 44.

Thus, the first quartile is 44.

The third quartile is the middle value of the lower-half of the data set.

The upper-half of the data set is:

56, 56, 57, 60, 62, 65, 69

The middle value of the data set is 60.

Thus, the third quartile is 60.

(c)

The range of a data set is the difference between the maximum and minimum value.

Maximum = 69

Minimum = 36

Compute the value of Range as follows:

$Range =Maximum-Minimum\\=69-36\\=33$

Thus, the value of range is 33.

The inter-quartile range is the difference between the first and third quartile value.

Compute the value of IQR as follows:

$IQR=Q_{3}-Q_{1}\\=60-44\\=16$

Thus, the inter-quartile range is 16.

(d)

Compute the variance of the data set as follows:

$s^{2}=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}\\=\frac{1}{15-1}[(55-52)^{2}+(56-52)^{2}+...+(65-52)^{2}]\\=100.143$

Thus, the variance is 100.143.

Compute the value of standard deviation as follows:

$s=\sqrt{s^{2}}=\sqrt{100.143}=10.01$

Thus, the standard deviation is 10.01.

(e)

An outlier is a data value that is different from the remaining values.

An outlier is a value that lies below 1.5 IQR of the first quartile or above 1.5 IQR of the third quartile.

Compute the value of Q₁ - 1.5 IQR as follows:

$Q_{1}-1.5QR=44-1.5\times 16=20$

Compute the value of Q₃ + 1.5 IQR as follows:

$Q_{3}+1.5QR=60-1.5\times 16=80$

The minimum value is 36 and the maximum is 69.

None of the values is less than 20 or more than 80.

Thus, there are no outliers in the data set.

(f)

Yes, the data provided indicates that the Walmart is meeting its goal for reducing the number of hourly employees

6 0

3 years ago