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krok68 [10]
3 years ago
12

What are the solutions to 2x^2+7y=4 ? Select all that apply.

Mathematics
1 answer:
liberstina [14]3 years ago
7 0

Answer:

x = -1/2 , 4

Step-by-step explanation:

1) If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.

2x+1=0

x−4=0

2) Set the first factor equal to 0.

2x+1=0

3) Subtract 1 from both sides of the equation.

2x=−1

4) Divide each term by 2 and simplify.

2x/2= −1/2

5) Cancel the common factor of 2.

x= −1/2

6) Move the negative in front of the fraction.

x = −1/2

7) Set the next factor equal to 0 and solve.

x=4

8) The final solution is all the values that make

(2x+1)(x−4) = 0 true.

9) x = −1/2 , 4

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Use substitution to solve the system. 5X+3Y=22 Y=2X-11
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Answer:

See below:

Step-by-step explanation:

Hello! My name is Galaxy and I will be helping you today. I hope you are having a nice day.

We can solve this problem in two steps, Comprehending, and Solving/Checking our answers. I'll be starting off with Comprehending.

Comprehending

We can solve the problem with substitution by finding out what one variable is equal to in terms of the second variable.

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We can do this either with Graphing, or Algebra. In this case, we need to use substitution, so it has to be Algebraically.

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Solving

We can solve the problem by first replacing y with its correct value in terms of x. Since we know the two equations, we can begin solving.

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We can solve it by inserting our y value into the y value of the second equation.

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