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Lelechka [254]
3 years ago
11

Find the missing side length. and how do i set up to solve?

Mathematics
1 answer:
nikitadnepr [17]3 years ago
6 0

Answer:

its 6 because the lines show they are parellel so it has to be equal to 18 and 12 plus 6 is 18

Step-by-step explanation:

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consider the quadratic functio. f(x)=x2-5x+6 what are the values of the coefficients and constant in the function​
eduard

Answer:

1and5 are coefficients6is a constant

Step-by-step explanation:

6 0
3 years ago
What is the solution of the system of equations? Show your work.
scZoUnD [109]

Answer:

1.Solve for y in 2x+y=-3

y=-3-2x

2. Substitute y= -3 - 2x into 4x-2y=10

8x+6=10

3 Solve for x in 8x+6=10

x=1/2

​

4. Substitute x=1/2 into y = - 3 - 2x

y= -4

5. So you get...,

x=1/2

y=−4

​

Step-by-step explanation:

you're welcome :)

3 0
2 years ago
Help with this one plz
kumpel [21]
Wouldn't it be 45? it's the minimum afterall
8 0
3 years ago
Read 2 more answers
A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at th
Valentin [98]

Answer:

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=12.8

The sample deviation calculated s=4.324 \approx 4.3

12.8-4.604\frac{4.324}{\sqrt{5}}=3.896    

12.8+ 4.604\frac{4.324}{\sqrt{5}}=21.704    

So on this case the 99% confidence interval would be given by (3.896;21.704)    

Step-by-step explanation:

Data: 10,9,20,13,12

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=12.8

The sample deviation calculated s=4.324

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=5-1=4

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,4)".And we see that t_{\alpha/2}=4.604

Now we have everything in order to replace into formula (1):

12.8-4.604\frac{4.324}{\sqrt{5}}=3.896    

12.8+ 4.604\frac{4.324}{\sqrt{5}}=21.704    

So on this case the 99% confidence interval would be given by (3.896;21.704)    

6 0
3 years ago
PLEASE ANSWER ASAP!!!! WILL GIVE BRAINLIEST TO CORRECT
Goshia [24]
I used my graphing calculator and it shows its graph C 

5 0
4 years ago
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