Answer:
k = 10
Explanation:
The initial polynomial is:

If f(-2) = 0, then when we replace x by -2, the result will be 0. It means that we can write the following equation:

Therefore, we can solve for k as follows:

So, the value of k is 10
Answer:
No. They are not in proportion
Step-by-step explanation:


So, they are not in proportion
4(5)=20
5(5)=25
4 groups of 6th grader
5 groups of 7th graders
Answer:
<h3>#5</h3>
<u>Given vertices:</u>
These have same x-coordinate, so when connected form a vertical segment.
<u>The length of the segment is:</u>
The area of the rectangle is 72 square units, so the horizontal segment has the length of:
<u>Possible location of the remaining vertices (to the left from the given):</u>
and
<h3>#6</h3>
<u>Similarly to previous exercise:</u>
- (5, -8) and (5, 4) given with the area of 48 square units
<u>The distance between the given vertices:</u>
<u>The other side length is:</u>
<u>Possible location of the other vertices (to the right from the given):</u>
and