Choice A is false because they are rounding to the nearest tenth (one decimal place) and not nearest hundredth (two decimal places)
Choice B is false as well because 3.825 should round to 3.83. The 5 at the end tells you to round up.
Choice C is false too. The value 3.824 should round to 3.82. Not sure how they got 3.81, so it seems like a deliberate trick question or silly answer.
Choice D is true. The three decimal values are rounded properly to the correct number of decimal places.
Therefore choice D is the answer
Answer:
Isn't it 18?
Step-by-step explanation:
Because you need to add 4 and 2 then multiply it with 3?
14 divided by 5 is 2.8 and 2.8 you can change 2.8 to 28/10 simplify that to 14/5 and turn it to a mixed number you get 2 4/8
<span>3x^2 + 18x + 15 = 0
15 + 18x + 3x2 = 0
3(5 + 6x + x2) = 0
</span>3((5 + x)(1 + x)) = 0
5 + x = 0
5 + -5 + x = 0 + -5
Combine like terms: 5 + -5 = 0
0 + x = 0 + -5
x = 0 + -5
x = -5
<span>--------------------------------------------
1 + x = 0
x=-1
-5,-1 </span>
Answer:
a)

b)
The total amount accrued, principal plus interest, from compound interest on an original principal of $ 4,200.00 at a rate of 3.6% per year compounded 12 times per year over 10 years is $5667.28.
Step-by-step explanation:
a. Write the function that represents the value of the account at any time, t.
The function that represents the value of the account at any time, t

where
P represents the principal amount
r represents Annual Rate
n represents the number of compounding periods per unit t, at the end of each period
t represents the time Involve
b) What will the value be after 10 years?
Given
The principal amount P = $4200
Annual Rate r = 3.6% = 3.6/100 = 0.036
Compounded monthly = n = 12
Time Period = t
To Determine:
The total amount A = ?
Using the formula

substituting the values


$
Therefore, the total amount accrued, principal plus interest, from compound interest on an original principal of $ 4,200.00 at a rate of 3.6% per year compounded 12 times per year over 10 years is $5667.28.