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2 years ago

Which of the following pairs of numbers contains like fractions?

Mathematics

1 answer:

Shalnov [3]2 years ago

6 0

Answer:

B.5/6 and 10/12

Step-by-step explanation:

The given values are;

$\frac{5}{6}$ and $\frac{10}{12}$

$\frac{10}{12}$ ,

reducing to the smallest term by dividing by 2;

is $\frac{5}{6}$

So;

$\frac{5}{6}$ and $\frac{10}{12}$ are both like fractions.

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Omg pls help ill give you 20 points

ElenaW [278]

Answer:

Step-by-step explanation:

Amount of water in tank 1 = amount of water in tank 2

30t +25 = -20t + 1000

Add 20t to both sides

30t + 20t + 25 = -20t + 20t + 1000

50t + 25 = 1000

Subtract 25 from both sides

50t + 25 - 25 = 1000 - 25

50t = 975

Divide both sides by 50

t = 975/50 = 39/2

$= 19 \frac{1}2}$

t = 19 minutes 30 seconds

After 19 1/2 minutes both tanks will have 610 liters of water

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2 years ago

The base of a cylindrical

KengaRu [80]

Answer:

Step-by-step explanation:

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1 year ago

Round 9,631.4725 to the nearest thousandth

pychu [463]

The answer would be 9,631.473. Since there is a 5 after the two, you round up one value. Hope this helps!

7 0

3 years ago

Read 2 more answers

What is 11 times 5/6

Inga [223]

Answer:

simplified form -

Exact form - 55/6

Decimal form - 9.16..

Mixed number form - 9 1/6

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into

Alex_Xolod [135]

Answer:

a) the length of the wire for the circle = $(\frac{60\pi }{\pi+4}) in$

b)the length of the wire for the square = $(\frac{240}{\pi+4}) in$

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

b= $\frac{y}{4}$

Area of the square which is L² can now be said to be;

$A_S=(\frac{y}{4})^2 = \frac{y^2}{16}$

On the otherhand; let the radius (r) of the circle be;

2πr = 60-y

$r = \frac{60-y}{2\pi }$

Area of the circle which is πr² can now be;

$A_C= \pi (\frac{60-y}{2\pi } )^2$

$=( \frac{60-y}{4\pi } )^2$

Total Area (A);

A = $A_S+A_C$

= $\frac{y^2}{16} +(\frac{60-y}{4\pi } )^2$

For the smallest possible area; $\frac{dA}{dy}=0$

∴ $\frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0$

If we divide through with (2) and each entity move to the opposite side; we have:

$\frac{y}{18}=\frac{(60-y)}{2\pi}$

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

$y= \frac{240}{\pi+4}$

∴ since $y= \frac{240}{\pi+4}$ , we can determine for the length of the circle ;

60-y can now be;

= $60-\frac{240}{\pi+4}$

= $\frac{(\pi+4)*60-240}{\pi+40}$

= $\frac{60\pi+240-240}{\pi+4}$

= $(\frac{60\pi}{\pi+4})in$

also, the length of wire for the square (y) ; $y= (\frac{240}{\pi+4})in$

The smallest possible area (A) = $\frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})$

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

4 0

3 years ago