Answer:
6546 students would need to be sampled.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of 
.
The margin of error is:
The dean randomly selects 200 students and finds that 118 of them are receiving financial aid.
This means that 
90% confidence level
So 
, z is the value of Z that has a p-value of 
, so 
.
If the dean wanted to estimate the proportion of all students receiving financial aid to within 1% with 90% reliability, how many students would need to be sampled?
n students would need to be sampled, and n is found when M = 0.01. So
Rounding up:
6546 students would need to be sampled.
This appears to be about rules of exponents as much as anything. The applicable "definitions, identities, and properties" are
i^0 = 1 . . . . . as is true for any non-zero value to the zero power
i^1 = i . . . . . . as is true for any value to the first power
i^2 = -1 . . . . . from the definition of i
i^3 = -i . . . . . = (i^2)·(i^1) = -1·i = -i
i^n = i^(n mod 4) . . . . . where "n mod 4" is the remainder after division by 4
1. = -3^4·i^(3·2+0+2·4) = -81·i^14 =
812. = i^((3-5)·2+0 = i^-4 =
13. = -2^2·i^(4+2+2+(-1+1+5)·3+0) = -4·i^23 =
4i4. = i^(3+(2+3+4+0+2+5)·2) = i^35 =
-i
Answer:
1st one is 9x-2
2nd is -3x -2
3rd one (put 1 instead of x in the given functions then calculate values and multiple )6
6.8 x 10^13 = 68,000,000,000,000
9.46 x10 ^12 = 9,460,000,000,000
6.8 x 10^13 * 1 light year / 9.46 x 10^12 = 7.188 light years.
Answer:
44
Step-by-step explanation:
6x +22 + 7x + 16 = 90
13x +38 =90
13x = 52
x = 4
7 x 4 +16 = 44
