Question

Help asaaaap explain please!!!!!

Answer 1

Answer:

C

Step-by-step explanation:

Once

$\sqrt{xy} = 6$

We know that $xy = 36$

There are infinity values for $x, y$, but considering $x, y \in \mathbb{Z}$

Below we have all the solutions for $x, y$

Negative:

$\\x = -36 \text{ and } y = -1\\x = -18 \text{ and } y = -2\\x = -12 \text{ and } y = -3\\x = -9 \text{ and } y = -4\\x = -6 \text{ and } y = -6\\x = -4 \text{ and } y = -9\\x = -3 \text{ and } y = -12\\x = -2 \text{ and } y = -18\\x = -1 \text{ and } y = -36$

Positives:

$x = 36 \text{ and } y = 1\\x = 18 \text{ and } y = 2\\x = 12 \text{ and } y = 3\\x = 9 \text{ and } y = 4\\x = 6 \text{ and } y = 6\\x = 4 \text{ and } y = 9\\x = 3 \text{ and } y = 12\\x = 2 \text{ and } y = 18\\x = 1 \text{ and } y = 36$

We can see that $x + y \neq 18$