Question 5 is C
To find how much she made from her sales, we multiply her sales by the decimal from of the commission.
32000*0.08 = 2560
Then we add this to her base pay (2560+1500) to get 4060
Question 6 is B
First, you can distribute the 1/2 to get 2-y
Then you can combined all terms that have a y
Your final answer is -3(1/2)+2
That would be
3x^2 + 4x - 60 - (3x^2 - x + 200)
= 4x - 60 + x - 200
= 5x - 260 Answer
.05 is equal to 5%
So for every dollar the mark up is .05cents
So if you times $81 by .05 this will give you the mark up because each of the 81$ needs .05 added to it.
So $4.05 Is the mark up
And
The cost would be markup and original added together
Answer:
77%
Step-by-step explanation:
Given the following :
Probability of winning both games = 50%
Probability of winning just the first game = 65%
Let the probability of winning the ;
First game = p(A) = 65%
Second game = p(B)
Both games = p(A and B) = 50%
What is the probability that the team will win the 2nd game given that they have already won the first game
The above question is a conditional probability question :
Probability of winning the second Given that they've already won the first = p(B | A)
p(B | A) = (A and B) / p(A)
p(B | A) = 50% / 65%
p(B | A) = 0.5 / 0.65
p(B | A) = 0.7692307
= 76.9% = 77%
Answer: P/6
I hope this helps!
