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nasty-shy [4]
3 years ago
10

Heat can transfer between two objects touching one another. What type of heat transfer is this? What will the temperature of bot

h objects be after these objects remain in contact for a long period of time?
Biology
1 answer:
lara [203]3 years ago
7 0

Answer:

Heat can transfer between two objects touching one another. What type of heat transfer is this? What will the temperature of both objects be after these objects remain in contact for a long period of time?

Explanation:

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Without enzymes, what would happen to the rate of chemical reactions?
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Consider the results of a testcross performed on an organism heterozygous for 2 genes. For each scenario of gene arrangement for
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Answer:

Following are the answer to the given points:

Explanation:

  • Unlinked - Nonrecombinant progeny (50%), recombinant progeny (50%)
  • Fully related genetics - 100% non-recombining genetic progeny (parental)
  • Incomplete connection of genes > 50% non-recombinant progeny < 50% crossover offspring. Connected genes

Mendel had established some essential concepts concerning inherited mechanisms such as the patterns of transmission of genes to offspring depending on their chromosomal placements. This same notion of linkage was offered to describe the pattern of the legacy of alleles on its chromosomal position.

Two different chromosomes have specific isoforms – for example, A and B which have two different features. As just a result, 50 percent of gametes are parental throughout type AB, and the other 50 percent of a recombinant in zygotes are quasi (aB & Ab) and 50 percent of the progenies that outcome from this mixture of gametes, therefore, are nonrecombinant in 50% and the cloned in 50 percent of the genetic makeup AaBb.

With two fully linked genes, e.g they exist on the very same chromosome and no cross-over occurs, all gametes are similar to parent types (AB and ab), like they do not split themself nor are diverse and culturally produced (nonrecombinants).

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3 years ago
Ep-12 when someone falls overboard, what action should the skipper take?
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. For the following give the mRNA, tRNA and amino acid (a.a.) sequence that will be created:
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<span>mRNA: UACAUGGCCUUACGCUAA tRNA: AUG UAC CGG AAU GCG AUU a.a: Tyrosine, Methionine, Alanine, Leucine, and Arginine DNA has 4 different bases, they are Adenine (A), cytosine (C), guanine (G), and Thymine (T). RNA also has 4 bases with three of them being identical to the DNA bases and Thymine being replaced with Uracil (U). These bases are generally represented by the 1st letter of their names. Each of the bases will join with a complementary base, so A always pairs with T or U, and C will pair with G. So to create the mRNA, simply replace every A with a U, every C with a G, every G with a C, and finally, every T with a A. So mRNA: UACAUGGCCUUACGCUAA Now for tRNA, there's a slight twist. It only comes in 3 base codons, You won't find a sequence of tRNA other than in 3 base codons. And each of those codons will be uniquely paired with an amino acid. In the ribosomes, the mRNA will be sequentially scanned 3 bases at a time allowing for a matching tRNA sequence to bind to the exposed 3 bases, this will cause the next amino acid to be bound into the protein being constructed. So split the mRNA into 3 base sequences and calculate the complement to get the tRNA. A simple shortcut is to look at the original DNA sequence and simply replace a T bases with U. So tRNA: AUG UAC CGG AAU GCG AUU Notice the spaces every 3rd base. THIS IS REQUIRED. These is no continuous length of tRNA. You'll only find it in 3 base lengths and each of them will be bound with an amino acid. For the amino acid that's coded to the RNA, you'll need to use a lookup table in your text book, or one you can find online. Then it's a simple matter of matching each 3 base sequence to the amino acid. For the sequence given we have: AUG - Tyrosine UAC - Methionine CGG - Alanine AAU - Leucine GCG - Arginine AUU - STOP Notice the AUU doesn't decode to a specific amino acid. It instead indicates to the ribosome to stop the production of the protein. So the amino acid sequence for the originally given DNA sequence is: Tyrosine, Methionine, Alanine, Leucine, and Arginine.</span>
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In squirrels, the gene for gray fur (G) is dominant over the gene for black fur (g). If 50% of a large litter of squirrels are g
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Gg and gg will most likely be the parental cross.

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