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Diano4ka-milaya [45]
3 years ago
6

If g = 1/5 how much is 15 g

Mathematics
2 answers:
dexar [7]3 years ago
5 0
The answer to this question is 3. to solve this, multiple g, which is 1/5, by 15. This will give you 15/5. now, divide 15 by 5 and you will get 3. I hope this helps!
alina1380 [7]3 years ago
5 0

15g

Substitute 1/5 for g

15(1/5)

Make 15 become an improper fraction

15/1(1/5)

Multiply the numerators and denominators together

15/5

Divide

Final Answer: 3

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Do male and female servers work the same number of hours? A sample of 25 female servers worked an average of 26 hours per week,
Vera_Pavlovna [14]

Answer:

Step-by-step explanation:

Given that

Group   Group One     Group Two  

Mean       26.00 23.00

SD                 2.00 4.00

SEM         0.40 1.21

N                     25     11    

where group I represents female servers and group II male servers.

We have to calculate confidence interval for 90% for difference in means

The mean of Group One minus Group Two equals 3.00

df = 34  

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t critical = 2.034 for 90% df 34

Hence confid. interval at 90%

=Mean diff ±2.034 * std error of diff

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5 0
2 years ago
The bucket is 30% full. when half way empty it is 15% full. how full is the bucket when 250% full?
Sunny_sXe [5.5K]

Answer:

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Step-by-step explanation:

divide 250% by 2

7 0
2 years ago
Read 2 more answers
On the first part of her trip Natalie rode her bike 16 miles and on the second part of the trip she rode her bike 42 miles. Her
-BARSIC- [3]

Answer:

14 mph   ( average speed during the second part of the trip )

Step-by-step explanation:

Let´s call  "x"  the average speed during the first part then

t = 5 hours

t  =  t₁  +  t₂        t₁   and  t₂   times during part 1 and 2 respectively

l = t*v           (  distance is speed by time )      t =  l/v

First part

t₁  = 16/x        and      t₂  = 42 / ( x + 6)

Then

t =   5   =  16/x   +   42 /(x + 6)

5 = [ 16 * ( x  +  6 ) +  42 * x ] / x* ( x + 6 )

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5*x²  -  28*x  -  96  =  0

We obtained a second degree equation, we will solve for x and dismiss any negative root since negative time has not sense

x₁,₂  =   [28 ± √ (28)² + 1920  ] / 10

x₁,₂  = ( 28  ± √2704 )/ 10

x₁  = 28  -  52 /10        we dismiss that root

x₂  = 80/10

x₂  =  8 mph       average speed during the first part, and the average speed in the second part was 6 more miles than in the firsst part. then the average spedd dring the scond part was 8 + 6 = 14 mph

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6 0
3 years ago
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