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3 years ago

Which is the better buy? 12 bars of soap for $10.00 or 5 bars of soap for $4.00

Mathematics

2 answers:

Butoxors [25]3 years ago

6 0

It is cheaper to buy 2 5packs because your total will be $8 not $10 so you end up saving $2 a dollar per pack

likoan [24]3 years ago

3 0

5 Bars of soap for $4.00 Why? Because you if you buy two it cost $8.00 or buy three pack and you'll get 15 for $12.00

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Peter plays basketball. In one game, he needs to score at least 38 points to have a

earnstyle [38]

2x + 3y > 38

I am currently on mobile, but the > should have a solid line beneath. I know that 2x + 3y needs to be greater than or equal to 38, since if he scores less than 38 points he won’t meet his season high of 1,200.

7 0

3 years ago

THERE ARE 60 INCHES IN 5 FEET- HOW MANY INCHS ARE IN 8 FEET

Daniel [21]

Answer: 96 inches in 8 feet

Step-by-step explanation:

12 inches in one foot

12x8=96

5 0

2 years ago

A cylinder and cone have the same height and radius. The height of each is 5 cm, and the radius is 2 cm. Calculate the volume of

never [62]

Answer:

The volume of a cylinder is 62.8 cm and the volume of a cone is 20.9 cm³ .

Step-by-step explanation:

Formula

$Volume\ of\ a\ cylinder = \pi r^{2} h$

$Volume\ of\ a\ cone = \pi r^{2} \frac{h}{3}$

Where r is the radius and h is the height .

As given

A cylinder and cone have the same height and radius. The height of each is 5 cm, and the radius is 2 cm.

$\pi = 3.14$

Thus

$Volume\ of\ a\ cylinder =3.14\times 5\times 2\times 2$

= 62.8 cm³

Thus the volume of a cylinder is 62.8 cm³ .

$Volume\ of\ a\ cone = 3.14\times 2\times 2\times frac{5}{3}$

$Volume\ of\ a\ cone =\frac{5\times 3.14\times 2\times 2}{3}$

$Volume\ of\ a\ cone =\frac{62.8}{3}$

= 20.9 (Approx) cm³

Thus the volume of a cone is 20.9 cm³ .

Therefore the volume of a cylinder is 62.8 cm and the volume of a cone is 20.9 cm³ .

8 0

3 years ago

Can someone please help me

Ilya [14]

I believe it is -81k^2

-27k^3-81k^2-81k-27

6 0

3 years ago

Find the directional derivative of the function at the given point in the direction of the vector v. h(r, s, t) = ln(3r + 6s + 9

vodka [1.7K]

Answer:

$D_\overrightarrow{\rm v}$ $h(r,s,t)=(\frac{2}{7}\overrightarrow{\rm i})*(\frac{1}{r+2s+3t})+(\frac{6}{7}\overrightarrow{\rm j})*(\frac{2}{r+2s+3t})+(\frac{3}{7}\overrightarrow{\rm k})*(\frac{3}{r+2s+3t})$

Step-by-step explanation:

First, let’s check to see if the direction vector is a unit vector:

$||v||=\sqrt{(14)^{2} +(42)^{2} +(21)^{2} } =\sqrt{2401} =49$

It’s not a unit vector. therefore let's divide the vector by its magnitude in order to convert it into a unit vector:

$\overrightarrow{\rm v}=(\frac{14}{49}\overrightarrow{\rm i})+(\frac{42}{49}\overrightarrow{\rm j})+(\frac{21}{49}\overrightarrow{\rm k})= (\frac{2}{7}\overrightarrow{\rm i})+(\frac{6}{7}\overrightarrow{\rm j})+(\frac{3}{7}\overrightarrow{\rm k})$

Now, the directional derivative is given by:

$D_\overrightarrow{\rm v}$ $h(r,s,t)=\frac{\partial h(r,s,t)}{\partial r}\overrightarrow{\rm i} + \frac{\partial h(r,s,t)}{\partial s}\overrightarrow{\rm j} + \frac{\partial h(r,s,t)}{\partial t}\overrightarrow{\rm k}$

So let's calculate the partial derivates:

$\frac{\partial }{\partial r} ln(3r+6s+9t)=\frac{3}{3r+6s+9t}=\frac{1}{r+2s+3t}$

$\frac{\partial }{\partial s} ln(3r+6s+9t)=\frac{6}{3r+6s+9t}=\frac{2}{r+2s+3t}$

$\frac{\partial }{\partial t} ln(3r+6s+9t)=\frac{9}{3r+6s+9t}=\frac{3}{r+2s+3t}$

Therefore:

3 0

3 years ago