Answer:
Samuel's hourly rate after n seasons with the company is f(n)= 12.50 + 0.35*n. After 18 seasons with the company, Samuel's hourly rate will be 18.8 $ /hr.
Step-by-step explanation:
You know that Samuel's starting pay is $12.50/hr and for each season Samuel remains with the company, he receives a $0.35/hr raise.
Samuel's hourly rate after n seasons at the company will then be:
f(n)= 12.50 + 0.35*n
To determine the hourly rate after 18 seasons, you must replace the value n with 18:
f(18)= 12.50 + 0.35*18
Solving you get:
f(18)= 12.50 + 6.3
f(18)= 18.8
<u><em>Samuel's hourly rate after n seasons with the company is f(n)= 12.50 + 0.35*n. After 18 seasons with the company, Samuel's hourly rate will be 18.8 $ /hr. </em></u>
D Elion and her colleagues were responsible for developing important drugs
Answer:
Step-by-step explanation:
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Answer:
a) 7/4 b) 5 c) 2
Step-by-step explanation:
Logrithmic Rule for a and b
Let a, M, N be positive real numbers.
a)
logaM - logaN = loga(M/N)
log9(7) - log9(4) = log9 (7/4)
b)
logaM + logaN = logaMN
log2 (x) + log2(9) = log2(45)
x9=45
(x9)/9 = 45/9
x = 5
c)
Change of base formula.
logb(x)=logd(b)/logd(x)
x log6(5) = log6(25) divide each term by log6(5)
x log6(5) / log6(5) = log6(25) / log6(5) Cancel common factor log6(5)
x = log6(25) / log6(5)
x = log6(5^2) / log6(5)
Expand log6(5^2) by moving 2 outside the logarithm.
x = 2log6(5) / log6(5) cancel the like term log6(5)
x = 2
Answer:
257/1000
Step-by-step explanation:
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